Apply Volume Formulas - 8th Grade Math

  1. A cylinder has height hh. If radius doubles from rr to 2r2r, how does volume change?
    Volume quadruples: V→4VV \to 4V. Volume is proportional to r2r^2, so doubling rr quadruples VV.
  2. State the formula for the volume of a sphere with radius rr.
    V=43πr3V=\frac{4}{3}\pi r^3. Sphere volume uses radius cubed with coefficient 43π\frac{4}{3}\pi.
  3. A sphere has diameter 88. What is VV in terms of π\pi?
    2563π\frac{256}{3}\pi. With r=4r = 4, V=43π(4)3=2563πV = \frac{4}{3}\pi(4)^3 = \frac{256}{3}\pi.
  4. A cylinder has V=72πV = 72\pi and r=3r = 3. What is the height hh?
    h=8h = 8. Solve 72π=π(3)2h72\pi = \pi(3)^2h to get h=729=8h = \frac{72}{9} = 8.
  5. What is the volume of a cone with diameter 88 and height 99 in terms of π\pi?
    48π48\pi. Diameter 8 gives r=4r=4; V=13π(42)(9)=48πV=\frac{1}{3}\pi(4^2)(9)=48\pi.
  6. Find the height hh of a cone with volume V=12πV=12\pi and radius r=3r=3.
    h=4h=4. From 12π=13π(3)2h12\pi=\frac{1}{3}\pi(3)^2h, solve 12π=3πh12\pi=3\pi h for hh.
  7. What is the volume of a cone with r=3r = 3 and h=5h = 5? (Leave in terms of π\pi.)
    15π15\pi. Apply V=13πr2h=13π(3)2(5)=15πV = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi(3)^2(5) = 15\pi.
  8. Find and correct the error: A student wrote cylinder volume as V=2πrhV=2\pi rh.
    Correct: V=πr2hV=\pi r^2h. Student confused cylinder volume with lateral surface area formula.
  9. Identify the meaning of hh in the formulas V=πr2hV=\pi r^2h and V=13πr2hV=\frac{1}{3}\pi r^2h.
    hh is the perpendicular height. Vertical distance from base to top.
  10. A sphere's radius doubles from rr to 2r2r. By what factor does the volume change?
    Volume increases by 88: V→8VV \to 8V. Volume is proportional to r3r^3, so doubling rr multiplies VV by 88.
  11. Find the radius rr of a cylinder with volume V=64πV=64\pi and height h=16h=16.
    r=2r=2. From 64π=πr2(16)64\pi=\pi r^2(16), divide by 16π16\pi to get r2=4r^2=4.
  12. A sphere has V=288πV = 288\pi. What is the radius rr?
    r=6r = 6. Solve 288π=43πr3288\pi = \frac{4}{3}\pi r^3 to get r3=216r^3 = 216, so r=6r = 6.
  13. What is the volume of a sphere with r=3r = 3? (Leave in terms of π\pi.)
    36π36\pi. Apply V=43πr3=43π(3)3=36πV = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi(3)^3 = 36\pi.
  14. What is the volume of a cylinder with diameter 1010 and height 44 in terms of π\pi?
    100π100\pi. Diameter 10 gives r=5r=5; V=π(52)(4)=100πV=\pi(5^2)(4)=100\pi.
  15. What is the radius of a sphere with diameter 1212?
    66. Radius is half the diameter: 12÷2=612÷2=6.
  16. Find the volume of a cylinder with diameter 1010 and height 33 in terms of π\pi.
    75π75\pi. Diameter 1010 gives r=5r=5, so V=π(5)2(3)V=\pi(5)^2(3).
  17. What is the radius rr of a sphere with V=43π(23)V=\frac{4}{3}\pi(2^3)?
    22. Given expression shows r3=8r^3=8, so r=2r=2.
  18. Identify the base area used in volume formulas for cylinders and cones when the radius is rr.
    B=πr2B=\pi r^2. Circular base area equals π\pi times radius squared.
  19. What is the volume of a cylinder with r=3r=3 and h=5h=5 in terms of π\pi?
    45π45\pi. Apply V=πr2hV=\pi r^2h with r=3r=3, h=5h=5: π(32)(5)=45π\pi(3^2)(5)=45\pi.
  20. What is the height hh of a cylinder with V=64πV=64\pi and r=4r=4?
    44. Solve 64π=π(42)h64\pi=\pi(4^2)h for hh: 64π=16πh64\pi=16\pi h, so h=4h=4.
  21. Which option is the correct volume formula for a cone: πr2h\pi r^2h or 13πr2h\frac{1}{3}\pi r^2h?
    V=13πr2hV=\frac{1}{3}\pi r^2h. Cone uses one-third of base times height.
  22. Choose the correct volume formula for a sphere: πr2h\pi r^2h, 43πr3\frac{4}{3}\pi r^3, or 13πr2h\frac{1}{3}\pi r^2h.
    V=43πr3V=\frac{4}{3}\pi r^3. Sphere formula has r3r^3, not r2hr^2h.
  23. Find the height hh of a cylinder with volume V=50πV=50\pi and radius r=5r=5.
    h=2h=2. From 50π=π(5)2h50\pi=\pi(5)^2h, divide by 25π25\pi to get h=2h=2.
  24. State the formula for the volume of a cone with radius rr and height hh.
    V=13πr2hV=\frac{1}{3}\pi r^2h. Cone volume is one-third of cylinder volume with same base and height.
  25. A cylinder and cone have the same rr and hh. What is VconeVcyl\frac{V_{\text{cone}}}{V_{\text{cyl}}}?
    13\frac{1}{3}. Cone volume is 13\frac{1}{3} of cylinder volume when dimensions match.
  26. What is the volume of a sphere with diameter 1212 in terms of π\pi?
    288π288\pi. Diameter 12 gives r=6r=6; V=43π(63)=288πV=\frac{4}{3}\pi(6^3)=288\pi.
  27. What is the volume of a cylinder with r=3r = 3 and h=5h = 5? (Leave in terms of π\pi.)
    45π45\pi. Apply V=πr2h=π(3)2(5)=45πV = \pi r^2 h = \pi(3)^2(5) = 45\pi.
  28. A sphere's radius is tripled. By what factor does the volume change?
    2727. Volume scales with r3r^3: if rr triples, VV increases by 33=273^3=27.
  29. Find the volume of a cone with r=3r=3 and h=5h=5 in terms of π\pi.
    15π15\pi. Apply V=13πr2h=13π(3)2(5)=13π(45)V=\frac{1}{3}\pi r^2h=\frac{1}{3}\pi(3)^2(5)=\frac{1}{3}\pi(45).
  30. Identify the meaning of rr in the formulas V=πr2hV=\pi r^2h and V=43πr3V=\frac{4}{3}\pi r^3.
    rr is the radius. Distance from center to edge of circular base.
  31. A cylinder has r=2r=2. If the height doubles, how does the volume change?
    Volume doubles. Volume V=πr2hV=\pi r^2h is proportional to height.
  32. Find the radius rr of a sphere with volume V=43π⋅27V=\frac{4}{3}\pi\cdot 27.
    r=3r=3. Since V=36π=43π(27)V=36\pi=\frac{4}{3}\pi(27), and 27=3327=3^3, so r=3r=3.
  33. Find the volume of a cone with diameter 1212 and height 44 in terms of π\pi.
    48π48\pi. Diameter 1212 gives r=6r=6, so V=13π(6)2(4)V=\frac{1}{3}\pi(6)^2(4).
  34. A cylinder has r=4r = 4. If height doubles from hh to 2h2h, how does volume change?
    Volume doubles: V→2VV \to 2V. Volume is proportional to height, so doubling hh doubles VV.
  35. What is the radius rr of a cylinder with V=36πV=36\pi and h=4h=4?
    33. Solve 36π=πr2(4)36\pi=\pi r^2(4) for rr: r2=9r^2=9, so r=3r=3.
  36. Find and correct the formula error: V=πr2hV = \pi r^2 h is claimed to be the volume of a cone.
    Correct: V=13πr2hV = \frac{1}{3}\pi r^2 h. Cone formula needs factor 13\frac{1}{3}, not just πr2h\pi r^2 h.
  37. If a cone and cylinder have the same rr and hh, what fraction of the cylinder's volume is the cone's volume?
    13\frac{1}{3}. Cone volume formula has factor 13\frac{1}{3} compared to cylinder.
  38. A cylinder and cone have the same rr and hh. What is VcylVcone\frac{V_{\text{cyl}}}{V_{\text{cone}}}?
    33. Cylinder volume is 33 times cone volume when dimensions match.
  39. A cone has diameter 1212 and height 99. What is VV in terms of π\pi?
    108π108\pi. With r=6r = 6, V=13π(6)2(9)=108πV = \frac{1}{3}\pi(6)^2(9) = 108\pi.
  40. A cylinder has diameter 1010 and height 44. What is VV in terms of π\pi?
    100π100\pi. With r=5r = 5, V=π(5)2(4)=100πV = \pi(5)^2(4) = 100\pi.
  41. Find the volume of a sphere with r=3r=3 in terms of π\pi.
    36π36\pi. Apply V=43πr3=43π(3)3=43π(27)V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi(3)^3=\frac{4}{3}\pi(27).
  42. A cone has V=12πV = 12\pi and r=2r = 2. What is the height hh?
    h=9h = 9. Solve 12π=13π(2)2h12\pi = \frac{1}{3}\pi(2)^2h to get h=364=9h = \frac{36}{4} = 9.
  43. What is the height hh of a cone with V=48πV=48\pi and r=6r=6?
    44. Solve 48π=13π(62)h48\pi=\frac{1}{3}\pi(6^2)h: 48π=12πh48\pi=12\pi h, so h=4h=4.
  44. What is the volume of a cone with r=3r=3 and h=5h=5 in terms of π\pi?
    15π15\pi. Apply V=13πr2hV=\frac{1}{3}\pi r^2h with r=3r=3, h=5h=5: 13π(9)(5)=15π\frac{1}{3}\pi(9)(5)=15\pi.
  45. Find and correct the error: A student wrote the sphere volume as V=4πr3V=4\pi r^3.
    Correct: V=43πr3V=\frac{4}{3}\pi r^3. Missing the fraction 13\frac{1}{3} in the coefficient.
  46. What is the radius if the diameter of a circular base is dd?
    r=d2r = \frac{d}{2}. Radius is half the diameter.
  47. Identify the missing factor: A cone has volume V=_πr2hV=\_\pi r^2h.
    13\frac{1}{3}. Cone formula has factor 13\frac{1}{3} before πr2h\pi r^2h.
  48. What is the volume of a sphere with r=3r=3 in terms of π\pi?
    36π36\pi. Apply V=43πr3V=\frac{4}{3}\pi r^3 with r=3r=3: 43π(27)=36π\frac{4}{3}\pi(27)=36\pi.
  49. State the formula for the volume of a cylinder with radius rr and height hh.
    V=πr2hV=\pi r^2h. Base area πr2\pi r^2 times height gives cylinder volume.
  50. Which option is the correct volume formula for a cylinder: πr2h\pi r^2h or 13πr2h\frac{1}{3}\pi r^2h?
    V=πr2hV=\pi r^2h. Cylinder uses full base times height, not one-third.
  51. What is the relationship between a cylinder's volume and a cone's volume with the same rr and hh?
    Vcyl=3VconeV_{\text{cyl}}=3V_{\text{cone}}. Cylinder holds three times cone's volume.
  52. What is the relationship between a cone's volume and a cylinder's volume with the same rr and hh?
    Vcone=13VcylV_{\text{cone}}=\frac{1}{3}V_{\text{cyl}}. Cone holds exactly one-third of cylinder's volume.
  53. Find the volume of a cylinder with r=3r=3 and h=5h=5 in terms of π\pi.
    45π45\pi. Apply V=πr2h=π(3)2(5)=π(9)(5)V=\pi r^2h=\pi(3)^2(5)=\pi(9)(5).
  54. Identify the correct base area formula for a circle with radius rr used in volume formulas.
    B=πr2B = \pi r^2. Circle area formula used as base in cylinder and cone volumes.

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