7th Grade Math (Common Core) • Ratios and Proportional Relationships

Unit Rates with Ratios of Fractions

Learn how to find how much of something you get for exactly one unit — even when the numbers are fractions.

Middle School Math emblem with sigma notation, geometric shapes, and a ruler.
Inside this lesson 10 sections 5 questions 7 figures

Section 1

Where Do Unit Rates Come From?

People have been comparing amounts since the very beginning of civilization. Whenever someone asked, "How much do I get for this?" they were thinking about a rate. The idea is as old as trading grain, measuring land, and building pyramids. Let's look at some key moments.

~3000 BCE • Ancient Egypt

Egyptian scribes kept careful records of how many loaves of bread could be made from a set amount of grain. They were already computing rates — like "loaves per bushel" — to make sure rations were fair.

~300 BCE • Ancient Greece

Euclid wrote about ratios in his famous book Elements. He showed how to compare two quantities and decide if they were in the same proportion, which is exactly what we do when we find unit rates.

~600–800 CE • Indian Mathematicians

Mathematicians like Brahmagupta developed clearer rules for working with fractions. Their work made it possible to compute rates even when the numbers weren't whole — the exact skill you'll learn today.

1600s–1700s • The Scientific Revolution

Scientists like Galileo needed to describe speeds such as "miles per hour." As experiments grew more precise, rates involving fractions became essential for physics, astronomy, and engineering.

Today • Everyday Life

You see unit rates everywhere: price per ounce at the grocery store, miles per gallon on a car, and calories per serving on a nutrition label. When those measurements involve fractions, you need the skill covered in this lesson.

Throughout history, the question has stayed the same: "How much per one?" When the quantities are whole numbers, the answer is a simple division. But what happens when you're dividing fractions by fractions? That's the problem this lesson solves.

Section 2

Core Definitions

Before we dive in, let's make sure four key ideas are crystal clear. These are the building blocks for everything that follows.

1

Ratio

A ratio compares two quantities. For example, "3 cups of flour to 2 cups of sugar" is the ratio 3 : 2. Ratios can also be written as fractions.
2

Rate

A rate is a special ratio that compares two quantities with different units — like miles and hours, or dollars and pounds.
3

Unit Rate

A unit rate tells you how much of the first quantity goes with exactly one of the second quantity. "60 miles per 1 hour" is a unit rate.
4

Complex Fraction

A complex fraction has a fraction in the numerator, the denominator, or both. Example: ½ over ¾. You simplify it by dividing the top fraction by the bottom fraction.

Here's the main idea of this lesson: when a rate is written as a fraction divided by another fraction, you can still find the unit rate. You just need to know how to divide fractions. That's it!

✦

KEY TAKEAWAY

Think of a unit rate like a "per one" answer. If you share ½ of a pizza equally among ¼ of an hour, the unit rate tells you how much pizza you'd eat in a whole hour at that pace. Finding it means dividing the top fraction by the bottom fraction.

Section 3

Seeing It Visually

Let's look at a picture to understand what a unit rate with fractions really means. Imagine you walk ¾ of a mile in ½ of an hour. How fast are you going per one hour?

Walking ¾ mile in ½ hour → How many miles per 1 hour?TIME (HOURS)0¼½¾1DISTANCE (MILES)0¼½¾11¼1½GIVEN: ¾ mi in ½ hr(solid shading)DOUBLED: 1½ mi in 1 hr(dashed extension)UNIT RATE¾ ÷ ½ = 1½ miles per hour
Number line diagram showing ¾ mile walked in ½ hour and how it extends to 1½ miles in 1 hour

In the diagram above, the top number line shows time and the bottom shows distance. The solid shading shows what was given: you walked ¾ mile in ½ hour. The dashed sections show what happens if you keep that same pace for the other half-hour. You'd walk another ¾ mile, reaching 1½ miles in 1 full hour. That's your unit rate!

Mathematically, we got there by dividing: ¾ ÷ ½ = ¾ × 2 = 3⁄2 = 1½. The next section shows you the step-by-step method for any problem like this.

Section 4

The Step-by-Step Method

Finding a unit rate when fractions are involved comes down to one big idea: divide the first quantity by the second quantity. Since both quantities might be fractions, you need to remember how to divide fractions. Here's the formula.

Unit Rate Formula

UnitRate=firstquantity/secondquantity=firstquantity÷secondquantityUnit Rate = first quantity / second quantity = first quantity ÷ second quantity

"First quantity" is what you're measuring. "Second quantity" is "per what."

And here's the rule for dividing fractions that makes it all work:

Dividing Fractions

(a/b)÷(c/d)=(a/b)×(d/c)=(a×d)/(b×c)(a/b) ÷ (c/d) = (a/b) × (d/c) = (a × d) / (b × c)

To divide by a fraction, multiply by its reciprocal (flip the second fraction).

Let's break the full process into three clear steps:

Step 1 — Set up the division

Write the rate as a fraction: the first quantity on top, the second quantity on the bottom. This might look like a "fraction over a fraction" — that's totally okay!

Step 2 — Keep, Change, Flip

Keep the first fraction the same. Change the division sign to a multiplication sign. Flip (find the reciprocal of) the second fraction. Then multiply straight across: numerator × numerator and denominator × denominator.

Step 3 — Simplify

Reduce the answer to lowest terms. If the answer is an improper fraction, you can also write it as a mixed number. Don't forget to attach the correct units — like "miles per hour" or "dollars per pound."

✦

KEY TAKEAWAY

Dividing fractions is like a recipe swap: you "flip" the second ingredient and then multiply. It's the same move every time — Keep, Change, Flip. Once you master that, unit rates with fractions are no harder than unit rates with whole numbers.

Section 5

Types of Unit Rate Problems

Unit rate problems with fractions show up in lots of different situations. The table below organizes the most common types you'll see. Notice that the setup is always the same: divide the "what" by the "per what."

ScenarioRate ExpressionUnit Rate
A painter uses ²⁄₃ gallon of paint for ¼ of a wall²⁄₃ gal ÷ ¼ wall2⅔ gal per wall
A recipe calls for ¾ cup of sugar for ½ batch¾ cup ÷ ½ batch1½ cups per batch
A runner covers ⅚ mile in ⅓ hour⅚ mi ÷ ⅓ hr2½ mi per hr
A store charges $⅘ for ⅔ lb of trail mix⅘ $ ÷ ⅔ lb$1⅕ per lb
A faucet leaks ⅛ gallon in ¾ hour⅛ gal ÷ ¾ hr⅙ gal per hr

Now let's see a visual flowchart that shows the decision process from start to finish.

STEP 1Identify the two quantitiesWhich is "what" and which is "per what"?STEP 2Keep · Change · FlipKEEP1st fraction staysCHANGE÷ becomes ×FLIP2nd fraction flipsSTEP 3Multiply, simplify, add unitsReduce to lowest terms or write as a mixed number✓ Unit Rate Found!
Flowchart showing three-step process: identify quantities, set up division (Keep-Change-Flip), simplify and label units

Section 6

Worked Example

Let's walk through a full problem together, nice and slow.

ℹ

Problem

Mia uses 2⁄3 of a cup of lemon juice for every 3⁄8 of a pitcher of lemonade. How many cups of lemon juice does she use per whole pitcher?

Worked Example: Mia's Lemonade

  1. 1

    Step 1 — Identify the quantities and set up the division

    The two quantities are ²⁄₃ cup of lemon juice and ³⁄₈ pitcher. We want "cups per pitcher," so cups go on top and pitchers go on the bottom.
    Unit Rate = ²⁄₃ ÷ ³⁄₈
  2. 2

    Step 2 — Keep, Change, Flip

    Keep ²⁄₃. Change ÷ to ×. Flip ³⁄₈ to get ⁸⁄₃.
    ²⁄₃ × ⁸⁄₃
  3. 3

    Step 3 — Multiply straight across

    Numerators: 2 × 8 = 16. Denominators: 3 × 3 = 9.
    (2 × 8) / (3 × 3) = 16/9
  4. 4

    Step 4 — Simplify and add units

    ¹⁶⁄₉ is already in lowest terms (16 and 9 share no common factor besides 1). As a mixed number: 16 ÷ 9 = 1 remainder 7, so ¹⁶⁄₉ = 1⁷⁄₉.
    1⁷⁄₉ cups of lemon juice per pitcher

That means for every full pitcher of lemonade, Mia needs a little more than 1¾ cups of lemon juice. Makes sense — if ²⁄₃ cup only fills ³⁄₈ of a pitcher, a whole pitcher needs a lot more juice!

Section 7

Whole-Number Rates vs. Fraction Rates

You already know how to find unit rates with whole numbers — like "150 miles in 3 hours → 50 miles per hour." Fraction unit rates use the exact same logic. The table below compares the two side by side so you can see how similar they really are.

FeatureWhole-Number RateFraction Rate
Example150 mi ÷ 3 hr¾ mi ÷ ½ hr
OperationRegular divisionDivision of fractions (Keep, Change, Flip)
Result50 mi/hr1½ mi/hr
Extra step?None — just divideFlip the second fraction, then multiply
When to simplifyIf the answer isn't a whole numberAlways check — reduce and convert to mixed number if needed
Common mistakesDividing in the wrong orderForgetting to flip, or flipping the wrong fraction
✦

KEY TAKEAWAY

Finding a unit rate with fractions is like following the same recipe but adding one extra ingredient. You still divide the "what" by the "per what." The only new step is that you flip the second fraction before you multiply. If you can divide fractions, you can find any unit rate!

Section 8

What Comes Next?

Now that you can compute unit rates with fractions, you're building a bridge to more advanced math. Here's a quick peek at where this skill leads.

This LessonComing Soon
Find a unit rate from a single ratio of fractionsUse unit rates to check if two ratios form a proportion
Work with simple fraction ÷ fractionSolve proportional equations where the unknown is in one of the fractions
Attach units (miles per hour, dollars per pound)Graph proportional relationships on a coordinate plane and interpret the constant of proportionality
Compute one rate at a timeCompare multiple unit rates to decide the better deal or the faster speed

Every proportional relationship you'll study in 7th grade and beyond relies on the idea of a unit rate. The skills you practiced today — dividing fractions and interpreting the result with units — will show up again and again in algebra, science, and real life. You're setting a strong foundation!

Section 9

Practice Problems

Try these five problems on your own. Start from the top and work your way down — they get a little harder each time. Click "Show Answer" when you're ready to check your work.

Question 1: Conceptual

In your own words, what does a unit rate tell you? If someone says the unit rate is "12 pages per hour," what does the "per hour" part mean?
Show answer
A unit rate tells you how much of one quantity you get for exactly one of the other quantity. When we say "12 pages per hour," the "per hour" means we're measuring how many pages are read in one single hour. The word "per" always signals "for each one." Nice work if you said something like that!

Question 2: Basic Calculation

A snail crawls 1⁄4 of a meter in 1⁄2 of an hour. What is the snail's speed in meters per hour?
Show answer
Set up the division: ¼ ÷ ½. Keep ¼, change ÷ to ×, flip ½ to ²⁄₁. ¼ × ²⁄₁ = ²⁄₄ = ½. The snail's speed is ½ meter per hour. That's pretty slow — but hey, it's a snail! 🐌

Question 3: Intermediate

A baker uses 5⁄6 of a cup of flour for 2⁄3 of a batch of cookies. How many cups of flour does the baker need for one whole batch?
Show answer
Unit rate = ⅚ ÷ ⅔. Keep ⅚, change ÷ to ×, flip ⅔ to ³⁄₂. ⅚ × ³⁄₂ = ¹⁵⁄₁₂. Simplify: 15 and 12 are both divisible by 3. ¹⁵⁄₁₂ = ⁵⁄₄ = 1¼. The baker needs 1¼ cups of flour per batch. Great job if you remembered to simplify!

Question 4: Applied / Word Problem

At a farmer's market, ¾ of a pound of organic blueberries costs $9⁄2 (which is $4.50). Meanwhile, ⅖ of a pound of regular blueberries costs $6⁄5 (which is $1.20). Find the unit price (dollars per pound) for each type. Which is cheaper per pound?
Show answer
Organic: ⁹⁄₂ ÷ ¾ = ⁹⁄₂ × ⁴⁄₃ = ³⁶⁄₆ = $6 per pound. Regular: ⁶⁄₅ ÷ ⅖ = ⁶⁄₅ × ⁵⁄₂ = ³⁰⁄₁₀ = $3 per pound. The regular blueberries are $3 per pound, which is cheaper than the organic blueberries at $6 per pound. By finding unit rates, you can compare prices even when the packages are different sizes!

Question 5: Challenge

Jayden runs 7⁄8 of a mile in 3⁄10 of an hour. Keisha runs 2⁄3 of a mile in 1⁄5 of an hour. Who has a faster speed (higher unit rate in miles per hour)? By how much?
Show answer
Jayden: ⁷⁄₈ ÷ ³⁄₁₀ = ⁷⁄₈ × ¹⁰⁄₃ = ⁷⁰⁄₂₄ = ³⁵⁄₁₂ = 2¹¹⁄₁₂ mph (about 2.917 mph). Keisha: ²⁄₃ ÷ ¹⁄₅ = ²⁄₃ × ⁵⁄₁ = ¹⁰⁄₃ = 3⅓ mph (about 3.333 mph). Keisha is faster! The difference: ¹⁰⁄₃ − ³⁵⁄₁₂. Common denominator of 12: ⁴⁰⁄₁₂ − ³⁵⁄₁₂ = ⁵⁄₁₂. Keisha runs ⁵⁄₁₂ mile per hour faster than Jayden. This problem combined unit rates with fraction subtraction — awesome work if you got it right!

Summary

Lesson Summary

Summary

A unit rate tells you how much of one quantity corresponds to exactly one of another. When the given amounts are fractions, you find the unit rate by setting up a complex fraction — the first quantity over the second — and then dividing. The key technique is Keep, Change, Flip: keep the first fraction, change division to multiplication, and flip the second fraction (use its reciprocal). After multiplying straight across, simplify your answer and attach the correct units.

This skill lets you compare prices, speeds, recipes, and other real-world rates even when the measurements aren't nice whole numbers. Whether it's dollars per pound, miles per hour, or cups per batch, the process is always the same: divide the "what" by the "per what," simplify, and interpret your answer in context.

Varsity Tutors • 7th Grade Mathematics (Common Core) • Unit Rates with Ratios of Fractions