Find Volume With Fractional Edge Lengths - 6th Grade Math

  1. Find the missing length ll if V=16V=\frac{1}{6}, w=12w=\frac{1}{2}, and h=23h=\frac{2}{3}.
    l=12l=\frac{1}{2}. Solve 16=l×12×23\frac{1}{6} = l \times \frac{1}{2} \times \frac{2}{3}; l=12l = \frac{1}{2}.
  2. What is the volume of a prism with l=112l=1\frac{1}{2}, w=23w=\frac{2}{3}, h=12h=\frac{1}{2}?
    12\frac{1}{2}. Convert: 112=321\frac{1}{2} = \frac{3}{2}, then 32×23×12=12\frac{3}{2} \times \frac{2}{3} \times \frac{1}{2} = \frac{1}{2}.
  3. Find the base area: l=56l=\frac{5}{6} and w=310w=\frac{3}{10}.
    14\frac{1}{4} square units. Base area = length × width = 56⋅310=1560=14\frac{5}{6} \cdot \frac{3}{10} = \frac{15}{60} = \frac{1}{4}.
  4. What is the volume of a prism with l=56l=\frac{5}{6}, w=35w=\frac{3}{5}, h=23h=\frac{2}{3}?
    13\frac{1}{3}. Multiply: 56×35×23=3090=13\frac{5}{6} \times \frac{3}{5} \times \frac{2}{3} = \frac{30}{90} = \frac{1}{3}.
  5. Choose the correct expression for volume: l=25l=\frac{2}{5}, w=34w=\frac{3}{4}, h=12h=\frac{1}{2}.
    V=25⋅34⋅12V=\frac{2}{5}\cdot\frac{3}{4}\cdot\frac{1}{2}. The volume formula requires multiplying all three dimensions together.
  6. What unit should be used for volume if edge lengths are measured in inches?
    cubic inches, in3\text{in}^3. Volume units are always the cube of the linear measurement unit.
  7. Find the missing width: V=16V=\frac{1}{6}, l=12l=\frac{1}{2}, h=23h=\frac{2}{3}.
    w=12w=\frac{1}{2}. Solve: 16=12⋅w⋅23\frac{1}{6} = \frac{1}{2} \cdot w \cdot \frac{2}{3}; w=1613=12w = \frac{ \frac{1}{6} }{ \frac{1}{3} } = \frac{1}{2}
  8. Which expression correctly represents the volume of a prism with edges 23\frac{2}{3}, 35\frac{3}{5}, and 52\frac{5}{2}?
    V=23×35×52V=\frac{2}{3}\times\frac{3}{5}\times\frac{5}{2}. Volume formula multiplies all three edge lengths.
  9. What is the volume of a prism with l=34l=\frac{3}{4}, w=23w=\frac{2}{3}, h=12h=\frac{1}{2}?
    14\frac{1}{4}. Multiply: 34×23×12=624=14\frac{3}{4} \times \frac{2}{3} \times \frac{1}{2} = \frac{6}{24} = \frac{1}{4}.
  10. Find the missing height hh if V=310V=\frac{3}{10}, l=35l=\frac{3}{5}, and w=12w=\frac{1}{2}.
    h=1h=1. Solve 310=35×12×h\frac{3}{10} = \frac{3}{5} \times \frac{1}{2} \times h; h=1h = 1.
  11. How many (14)\left(\frac{1}{4}\right)-edge unit cubes fit in a (12)×1×2\left(\frac{1}{2}\right)\times 1\times 2 prism?
    6464 cubes. Dimensions fit 2×4×8=642 \times 4 \times 8 = 64 cubes of size 14\frac{1}{4}.
  12. Identify the number of (12)\left(\frac{1}{2}\right)-edge unit cubes that fit in a 2×1×12\times 1\times 1 prism.
    1616 cubes. Each dimension fits 2÷12=42 \div \frac{1}{2} = 4 cubes, so 4×2×2=164 \times 2 \times 2 = 16.
  13. Find the volume of a box with l=45l=\frac{4}{5} ft, w=32w=\frac{3}{2} ft, and h=56h=\frac{5}{6} ft.
    1 ft31 \, \mathrm{ft}^3. Apply V=lwh=45×32×56=1V = lwh = \frac{4}{5} \times \frac{3}{2} \times \frac{5}{6} = 1.
  14. State the volume formula for a right rectangular prism using length, width, and height.
    V=lwhV=lwh. Volume equals length times width times height for rectangular prisms.
  15. Identify the number of (13)\left(\frac{1}{3}\right)-edge unit cubes that fit in a 1×1×11\times 1\times 1 prism.
    2727 cubes. Each dimension fits 1÷13=31 \div \frac{1}{3} = 3 cubes, so 33=273^3 = 27.
  16. Identify the volume of a prism 1×12×321 \times \frac{1}{2} \times \frac{3}{2} in cubic units.
    34\frac{3}{4} cubic unit. Apply V=lwh=1×12×32=34V = lwh = 1 \times \frac{1}{2} \times \frac{3}{2} = \frac{3}{4}.
  17. What units are used for volume if edge lengths are measured in units (not squared units)?
    Cubic units (units3^3). Volume is 3-dimensional, so units are cubed.
  18. Find and correct the error: A student wrote V=lw+hV=lw+h for a right rectangular prism.
    Correct: V=lwhV=lwh. Volume requires multiplication, not addition, of the three dimensions.
  19. How many (13)3\left(\frac{1}{3}\right)^3 unit cubes fill a 1×1×11\times 1\times 1 cube?
    2727 cubes. Each dimension fits 113=3\frac{1}{\frac{1}{3}} = 3 cubes, so 33=273^3 = 27 total.
  20. What is the volume of a prism with l=12l=\frac{1}{2}, w=12w=\frac{1}{2}, and h=12h=\frac{1}{2}?
    18\frac{1}{8} cubic unit. Apply V=lwh=12×12×12=18V = lwh = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}.
  21. Identify the volume of a prism with l=52l=\frac{5}{2}, w=25w=\frac{2}{5}, h=34h=\frac{3}{4}.
    34\frac{3}{4} cubic unit. Apply V=lwh=52×25×34=34V = lwh = \frac{5}{2} \times \frac{2}{5} \times \frac{3}{4} = \frac{3}{4}.
  22. Find VV if base area is b=38b=\frac{3}{8} and height is h=49h=\frac{4}{9}.
    16\frac{1}{6}. Use V=bhV = bh: 38×49=1272=16\frac{3}{8} \times \frac{4}{9} = \frac{12}{72} = \frac{1}{6}.
  23. What is the volume of a prism with l=12l=\frac{1}{2}, w=13w=\frac{1}{3}, h=14h=\frac{1}{4}?
    124\frac{1}{24}. Multiply: 12×13×14=124\frac{1}{2} \times \frac{1}{3} \times \frac{1}{4} = \frac{1}{24}.
  24. Find the volume using V=BhV=Bh: B=712B=\frac{7}{12} and h=27h=\frac{2}{7}.
    16\frac{1}{6} cubic units. Apply V=BhV=Bh: 712⋅27=1484=16\frac{7}{12} \cdot \frac{2}{7} = \frac{14}{84} = \frac{1}{6}.
  25. A box is 23\frac{2}{3} ft by 34\frac{3}{4} ft by 12\frac{1}{2} ft. Find its volume.
    14 ft3\frac{1}{4}\,\text{ft}^3. Apply V=lwhV=lwh: 23⋅34⋅12=624=14\frac{2}{3} \cdot \frac{3}{4} \cdot \frac{1}{2} = \frac{6}{24} = \frac{1}{4}.
  26. How many (12)3\left(\frac{1}{2}\right)^3 unit cubes fill a 1×1×11\times 1\times 1 cube?
    88 cubes. Each dimension fits 112=2\frac{1}{\frac{1}{2}} = 2 cubes, so 23=82^3 = 8 total.
  27. Identify the correct volume for a prism with l=32l=\frac{3}{2}, w=25w=\frac{2}{5}, h=56h=\frac{5}{6}.
    V=12V=\frac{1}{2}. Calculate: 32×25×56=3060=12\frac{3}{2} \times \frac{2}{5} \times \frac{5}{6} = \frac{30}{60} = \frac{1}{2}.
  28. Identify the volume using V=bhV=bh if b=56b=\frac{5}{6} and h=35h=\frac{3}{5}.
    12\frac{1}{2} cubic unit. Apply V=bh=56×35=12V = bh = \frac{5}{6} \times \frac{3}{5} = \frac{1}{2}.
  29. What is the total number of 12\frac{1}{2}-edge cubes in a prism 1×12×321 \times \frac{1}{2} \times \frac{3}{2}?
    66 cubes. Count: 2×1×3=62 \times 1 \times 3 = 6 cubes fit in the prism.
  30. What does bb represent in the formula V=bhV = bh for a right rectangular prism?
    bb is the area of the base. In this formula, base area replaces length times width.
  31. Identify the missing height hh if V=34V=\frac{3}{4} and b=12b=\frac{1}{2} for a right rectangular prism.
    h=32h=\frac{3}{2}. Solve V=bhV = bh: 34=12×h\frac{3}{4} = \frac{1}{2} \times h, so h=32h = \frac{3}{2}.
  32. What does BB represent in the formula V=BhV=Bh for a right rectangular prism?
    BB is the area of the base. In V=BhV=Bh, BB represents the two-dimensional area of the prism's base.
  33. Find the volume: l=34l=\frac{3}{4}, w=23w=\frac{2}{3}, h=12h=\frac{1}{2}.
    14\frac{1}{4} cubic units. Multiply: 34⋅23⋅12=624=14\frac{3}{4} \cdot \frac{2}{3} \cdot \frac{1}{2} = \frac{6}{24} = \frac{1}{4}.
  34. How many (14)3\left(\frac{1}{4}\right)^3 cubes fill a prism 12×34×1\frac{1}{2}\times\frac{3}{4}\times 1?
    2424 cubes. (1/21/4)⋅(3/41/4)⋅(11/4)=2⋅3⋅4=24(\frac{1/2}{1/4}) \cdot (\frac{3/4}{1/4}) \cdot (\frac{1}{1/4}) = 2 \cdot 3 \cdot 4 = 24.
  35. Find the missing width ww if V=29V=\frac{2}{9}, l=23l=\frac{2}{3}, and h=12h=\frac{1}{2}.
    w=23w=\frac{2}{3}. Solve 29=23×w×12\frac{2}{9} = \frac{2}{3} \times w \times \frac{1}{2}; w=23w = \frac{2}{3}.
  36. Identify the base area bb if a prism has l=34l=\frac{3}{4} and w=23w=\frac{2}{3}.
    12\frac{1}{2} square unit. Base area b=l×w=34×23=12b = l \times w = \frac{3}{4} \times \frac{2}{3} = \frac{1}{2}.
  37. State the volume formula for a right rectangular prism using length, width, and height.
    V=lwhV=lwh. Volume equals length times width times height for rectangular prisms.
  38. What is the volume of one unit cube with edge length 15\frac{1}{5}?
    1125\frac{1}{125} cubic unit. Volume of a cube = edge³ = (15)3=1125(\frac{1}{5})^3 = \frac{1}{125}.
  39. How many cubes of edge length 12\frac{1}{2} fit in a prism 1×1×11 \times 1 \times 1?
    88 cubes. Each dimension fits 1÷12=21 \div \frac{1}{2} = 2 cubes, so 23=82^3 = 8.
  40. If each unit cube has edge length 12\frac{1}{2}, what is the volume of one cube?
    18\frac{1}{8} cubic unit. Volume of a cube is edge cubed: (12)3=18(\frac{1}{2})^3 = \frac{1}{8}.
  41. What is the volume of a prism with l=25l=\frac{2}{5}, w=34w=\frac{3}{4}, h=56h=\frac{5}{6}?
    14\frac{1}{4}. Multiply: 25×34×56=30120=14\frac{2}{5} \times \frac{3}{4} \times \frac{5}{6} = \frac{30}{120} = \frac{1}{4}.
  42. Find VV if base area is b=512b=\frac{5}{12} and height is h=35h=\frac{3}{5}.
    14\frac{1}{4}. Use V=bhV = bh: 512×35=1560=14\frac{5}{12} \times \frac{3}{5} = \frac{15}{60} = \frac{1}{4}.
  43. Identify the base area expression for a prism with base sides ll and ww.
    b=lwb=lw. Base area of a rectangle is length times width.
  44. Identify the volume of a prism with l=32l=\frac{3}{2}, w=2w=2, and h=12h=\frac{1}{2}.
    32\frac{3}{2} cubic units. Apply V=lwh=32×2×12=32V = lwh = \frac{3}{2} \times 2 \times \frac{1}{2} = \frac{3}{2}.
  45. Find the missing height: V=310V=\frac{3}{10}, l=35l=\frac{3}{5}, w=12w=\frac{1}{2}.
    h=1h=1. Solve: 310=35⋅12⋅h\frac{3}{10} = \frac{3}{5} \cdot \frac{1}{2} \cdot h; h=3/103/10=1h = \frac{3/10}{3/10} = 1.
  46. State the volume formula for a right rectangular prism using base area and height.
    V=bhV=bh. When base area is known, multiply by height to find volume.
  47. What is the volume of a prism with l=78l=\frac{7}{8}, w=47w=\frac{4}{7}, h=12h=\frac{1}{2}?
    14\frac{1}{4}. Multiply: 78×47×12=28112=14\frac{7}{8} \times \frac{4}{7} \times \frac{1}{2} = \frac{28}{112} = \frac{1}{4}.
  48. Find the volume: l=12l=\frac{1}{2}, w=13w=\frac{1}{3}, h=14h=\frac{1}{4}.
    124\frac{1}{24} cubic units. Multiply: 12⋅13⋅14=124\frac{1}{2} \cdot \frac{1}{3} \cdot \frac{1}{4} = \frac{1}{24}.
  49. Identify the unit cube edge length: a cube has volume 127\frac{1}{27} cubic unit.
    edge length =13=\frac{1}{3}. Since V=s3V = s^3, if s3=127s^3 = \frac{1}{27}, then s=13s = \frac{1}{3}.
  50. Identify the volume of a prism with l=2l=2, w=3w=3, and h=12h=\frac{1}{2}.
    33 cubic units. Apply V=lwh=2×3×12=3V = lwh = 2 \times 3 \times \frac{1}{2} = 3.
  51. What units are used for volume if edge lengths are measured in units?
    Cubic units, written as units3\text{units}^3. Volume is 3-dimensional, so units are cubed.
  52. How many cubes of edge length 12\frac{1}{2} fit along an edge of length 32\frac{3}{2}?
    33 cubes. Divide edge length by cube size: 32div12=3\frac{3}{2} div \frac{1}{2} = 3.
  53. How many cubes of edge 14\frac{1}{4} fit along an edge of length 34\frac{3}{4}?
    33 cubes. Divide edge length by cube size: 3/41/4=34⋅4=3\frac{3/4}{1/4} = \frac{3}{4} \cdot 4 = 3.
  54. Identify the volume of a prism with l=23l=\frac{2}{3}, w=34w=\frac{3}{4}, h=2h=2.
    11 cubic unit. Apply V=lwh=23×34×2=1V = lwh = \frac{2}{3} \times \frac{3}{4} \times 2 = 1.
  55. What is the volume of one cube with edge length 13\frac{1}{3}?
    (13)3=127\left(\frac{1}{3}\right)^3=\frac{1}{27}. Cube volume is edge length cubed: (13)3=127(\frac{1}{3})^3 = \frac{1}{27}.
  56. Find the volume: l=112l=1\frac{1}{2}, w=23w=\frac{2}{3}, h=34h=\frac{3}{4}.
    34\frac{3}{4} cubic units. Convert: 112=321\frac{1}{2} = \frac{3}{2}, then 32⋅23⋅34=1824=34\frac{3}{2} \cdot \frac{2}{3} \cdot \frac{3}{4} = \frac{18}{24} = \frac{3}{4}.
  57. Identify the missing width ww if V=3V=3, l=2l=2, and h=34h=\frac{3}{4} for a right rectangular prism.
    w=2w=2. Solve V=lwhV = lwh: 3=2×w×343 = 2 \times w \times \frac{3}{4}, so w=2w = 2.
  58. State the volume formula for a right rectangular prism using base area and height.
    V=BhV=Bh. Volume equals base area times height for any prism.

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