Multiply Multi-Digit Whole Numbers - 5th Grade Math

  1. When multiplying 63×2463 \times 24, why is a 00 placeholder used in the second partial product?
    Because the second partial product is in the tens place (×20\times 20). The 2 in 24 represents 20, not 2.
  2. Which estimate is closest to 298×51298\times 51: 1500015000, 3000030000, or 6000060000?
    1500015000. Round to 300×50=15000300 \times 50 = 15000 for estimation.
  3. What is the product 408×23408\times 23 using the standard algorithm?
    93849384. 408×3=1224408 \times 3 = 1224, 408×20=8160408 \times 20 = 8160, sum is 93849384.
  4. What is the product 1 024×61\,024\times 6 using the standard algorithm?
    61446144. 1024×6=6000+120+24=61441024 \times 6 = 6000 + 120 + 24 = 6144.
  5. What is the product 999×7999\times 7 using the standard algorithm?
    69936993. 9×7=639 \times 7 = 63, carry 66; repeat for each digit.
  6. What is the product 208×4208\times 4 using the standard algorithm?
    832832. 208×4=800+0+32=832208 \times 4 = 800 + 0 + 32 = 832.
  7. Find the product 325×12325\times 12 using the standard algorithm.
    39003900. 325×2=650325 \times 2 = 650, 325×10=3250325 \times 10 = 3250, sum is 39003900.
  8. What is the value of the carry in 79×879\times 8 after computing 9×8=729\times 8=72?
    77. Write 22, carry 77 tens from 7272.
  9. What is the product 123×45123 \times 45 using the standard algorithm?
    55355535. Add partial products: 123×5=615123×5=615 and 123×40=4920123×40=4920.
  10. What is the product 507×6507\times 6 using the standard algorithm?
    30423042. 507×6=3000+0+42=3042507 \times 6 = 3000 + 0 + 42 = 3042.
  11. What is the product 208×34208 \times 34 using the standard algorithm?
    70727072. Add partial products: 208×4=832208×4=832 and 208×30=6240208×30=6240.
  12. What is the first step in the standard algorithm for 34×2734\times 27?
    Multiply 77 by each digit of 3434 from right to left. Start with the ones digit of the bottom number.
  13. What is the product 305×4305 \times 4 using the standard algorithm?
    12201220. Multiply each digit by 4: 5×4=205×4=20, 0×4=00×4=0, 3×4=123×4=12.
  14. What is the product 48×748 \times 7 using the standard algorithm?
    336336. Multiply each digit of 48 by 7, carrying as needed.
  15. What is the product 46×3046 \times 30 using the standard algorithm?
    13801380. 46×3=13846×3=138, then multiply by 10 for the tens place.
  16. In 326×47326 \times 47, what place value does the first partial product (from 77) represent?
    Ones place value (it is 326×7326 \times 7). The 7 is in the ones place of 47.
  17. What is the product 236×40236\times 40 using the standard algorithm?
    94409440. Multiply by 4040 means multiply by 44 and add a zero.
  18. Identify the missing digit: 68×5=3□068\times 5=3\square 0.
    44. 68×5=34068 \times 5 = 340, so the missing digit is 44.
  19. What is the product 47×3247\times 32 using the standard algorithm?
    15041504. 47×2=9447 \times 2 = 94, 47×30=141047 \times 30 = 1410, sum is 15041504.
  20. What zero is placed in the second row when multiplying 47×3247\times 32 using the standard algorithm?
    A 00 is placed in the ones place of the second partial product. When multiplying by tens, shift one place left.
  21. What is the product 46×346\times 3 using the standard algorithm?
    138138. 46×3=(40×3)+(6×3)=120+1846 \times 3 = (40 \times 3) + (6 \times 3) = 120 + 18.
  22. What is the product 63×2463\times 24 using the standard algorithm?
    15121512. 63×4=25263 \times 4 = 252, 63×20=126063 \times 20 = 1260, sum is 15121512.
  23. What is the product 64×964 \times 9 using the standard algorithm?
    576576. 4×9=364×9=36, 6×9=546×9=54, carry 5 to get 576.
  24. In 326×47326 \times 47, what place value does the second partial product (from 44) represent?
    Tens place value (it is 326×40326 \times 40). The 4 is in the tens place of 47.
  25. What is the product 79×1279 \times 12 using the standard algorithm?
    948948. Add partial products: 79×2=15879×2=158 and 79×10=79079×10=790.
  26. What is the product 237×8237 \times 8 using the standard algorithm?
    18961896. Multiply each digit by 8, carrying when products exceed 9.
  27. Find and correct the error: In 25×3425 \times 34, a student shifts the 33 partial product by 22 places.
    Shift by 11 place because 33 is in the tens place (3030). 3 in 34 is tens, so shift once, not twice.
  28. What is the product 407×26407 \times 26 using the standard algorithm?
    1058210582. Add partial products: 407×6=2442407×6=2442 and 407×20=8140407×20=8140.
  29. What is the first step in the standard algorithm to multiply 347×6347 \times 6?
    Multiply 66 by the ones digit: 6×76 \times 7. Start with the rightmost digit of the first number.
  30. What is the product 412×5412 \times 5 using the standard algorithm?
    20602060. 2×5=102×5=10, 1×5=51×5=5, 4×5=204×5=20, giving 2060.
  31. What is the product 508×60508 \times 60 using the standard algorithm?
    3048030480. 508×6=3048508×6=3048, then multiply by 10 for the tens place.
  32. What does the carried digit represent in 58×658\times 6 when 8×6=488\times 6=48?
    It represents 44 tens to add to the next product. The carried digit shows tens from the ones multiplication.
  33. What is the product 312×28312 \times 28 using the standard algorithm?
    87368736. Add partial products: 312×8=2496312×8=2496 and 312×20=6240312×20=6240.
  34. What does the carried digit represent in 58×658 \times 6 when 6×8=486 \times 8 = 48?
    It represents 44 tens to add in the next place value. The 4 from 48 carries to the tens column.
  35. What is the product 705×14705\times 14 using the standard algorithm?
    98709870. 705×4=2820705 \times 4 = 2820, 705×10=7050705 \times 10 = 7050, sum is 98709870.
  36. In the standard algorithm for 63×2463\times 24, what place value does the second partial product represent?
    It represents multiplying by 22 tens (the 2020). The 22 in 2424 is in the tens place, so multiply by 2020.
  37. What is the product 125×8125\times 8 using the standard algorithm?
    10001000. 125×8=1000125 \times 8 = 1000 (or 8×125=8×100088 \times 125 = 8 \times \frac{1000}{8}).
  38. What is the product 312×15312\times 15 using the standard algorithm?
    46804680. 312×5=1560312 \times 5 = 1560, 312×10=3120312 \times 10 = 3120, sum is 46804680.
  39. What is the product 906×3906 \times 3 using the standard algorithm?
    27182718. Multiply each digit by 3: 6×3=186×3=18, 0×3=00×3=0, 9×3=279×3=27.
  40. What is the product 23×4523 \times 45 using the standard algorithm?
    10351035. Add partial products: 23×5=11523×5=115 and 23×40=92023×40=920.

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