Find Area With Fractional Sides - 5th Grade Math

  1. Identify the unit square side length used to tile a 34\frac{3}{4} by 23\frac{2}{3} rectangle.
    112\frac{1}{12}. LCM of denominators 4 and 3 is 12, so unit square has side 112\frac{1}{12}.
  2. What is 72×114472 \times \frac{1}{144} (the tiled area for the 34\frac{3}{4} by 23\frac{2}{3} rectangle)?
    12\frac{1}{2}. 72×1144=72144=1272 \times \frac{1}{144} = \frac{72}{144} = \frac{1}{2}, confirming the tiled area.
  3. Compute 35×47\frac{3}{5} \times \frac{4}{7} to match the tiled area model.
    1235\frac{12}{35}. Multiply numerators and denominators: 3×45×7\frac{3 \times 4}{5 \times 7}.
  4. What is the area of a rectangle with side lengths 34\frac{3}{4} and 25\frac{2}{5}?
    310\frac{3}{10}. Multiply: 34×25=620=310\frac{3}{4} \times \frac{2}{5} = \frac{6}{20} = \frac{3}{10}.
  5. What is the area of a rectangle with side lengths 1121\frac{1}{2} and 23\frac{2}{3}?
    11. Convert: 112=321\frac{1}{2} = \frac{3}{2}, then 32×23=1\frac{3}{2} \times \frac{2}{3} = 1.
  6. Identify the unit square side lengths used to tile a 34\frac{3}{4} by 23\frac{2}{3} rectangle.
    14\frac{1}{4} by 13\frac{1}{3}. Use denominators of each fraction as tile dimensions.
  7. What is the area of a rectangle with side lengths 49\frac{4}{9} and 35\frac{3}{5}?
    415\frac{4}{15}. Multiply: 49×35=1245=415\frac{4}{9} \times \frac{3}{5} = \frac{12}{45} = \frac{4}{15}.
  8. What is the area of a rectangle with side lengths 512\frac{5}{12} and 67\frac{6}{7}?
    514\frac{5}{14}. Multiply: 512×67=3084=514\frac{5}{12} \times \frac{6}{7} = \frac{30}{84} = \frac{5}{14}.
  9. What is the area of a 34\frac{3}{4} by 23\frac{2}{3} rectangle (in square units)?
    12\frac{1}{2} square unit. Multiply: 34×23=612=12\frac{3}{4} \times \frac{2}{3} = \frac{6}{12} = \frac{1}{2}.
  10. How many 13\frac{1}{3}-length segments fit along a side of length 23\frac{2}{3}?
    22. Divide: 23÷13=2\frac{2}{3} \div \frac{1}{3} = 2.
  11. How many tiles are in an array with 33 columns and 44 rows?
    1212 tiles. Total tiles = rows × columns = 4×3=124 \times 3 = 12.
  12. What is the area of a rectangle with side lengths 310\frac{3}{10} and 56\frac{5}{6}?
    14\frac{1}{4} square unit. Multiply: 310×56=1560=14\frac{3}{10} \times \frac{5}{6} = \frac{15}{60} = \frac{1}{4}.
  13. How many 112\frac{1}{12} by 112\frac{1}{12} tiles fit in a 34\frac{3}{4} by 23\frac{2}{3} rectangle?
    7272 tiles. 34112=9\frac{\frac{3}{4}}{\frac{1}{12}} = 9 tiles wide, 23112=8\frac{\frac{2}{3}}{\frac{1}{12}} = 8 tiles tall, so 9×8=729 \times 8 = 72.
  14. Identify the missing side length if A=310A = \frac{3}{10} and one side is 34\frac{3}{4}.
    25\frac{2}{5}. Divide area by known side: 310÷34=310×43=25\frac{3}{10} \div \frac{3}{4} = \frac{3}{10} \times \frac{4}{3} = \frac{2}{5}.
  15. What total area is covered by 1212 tiles of area 135\frac{1}{35} each?
    1235\frac{12}{35}. Total area = tiles × area per tile = 12×13512 \times \frac{1}{35}.
  16. Identify the unit fraction side length of each tile to model 35×47\frac{3}{5} \times \frac{4}{7}.
    15\frac{1}{5} by 17\frac{1}{7}. Use denominators of each fraction as tile dimensions.
  17. What is the area of a rectangle with side lengths 23\frac{2}{3} and 35\frac{3}{5}?
    25\frac{2}{5} square units. Multiply: 23×35=615=25\frac{2}{3} \times \frac{3}{5} = \frac{6}{15} = \frac{2}{5}.
  18. How many 15\frac{1}{5}-wide columns fit across a length of 35\frac{3}{5}?
    33 columns. 35÷15=3\frac{3}{5} \div \frac{1}{5} = 3 columns fit exactly.
  19. What is the area of a rectangle with side lengths 910\frac{9}{10} and 29\frac{2}{9}?
    15\frac{1}{5} square unit. Multiply: 910×29=1890=15\frac{9}{10} \times \frac{2}{9} = \frac{18}{90} = \frac{1}{5}.
  20. Using tiling, what is the area of a 34\frac{3}{4} by 23\frac{2}{3} rectangle?
    12\frac{1}{2} square unit. 66 tiles each with area 112\frac{1}{12}: 6×112=126 \times \frac{1}{12} = \frac{1}{2}.
  21. What is the area of one tile with side length 112\frac{1}{12}?
    1144\frac{1}{144} square unit. Square with side 112\frac{1}{12} has area 112×112=1144\frac{1}{12} \times \frac{1}{12} = \frac{1}{144}.
  22. What is the area of a rectangle with side lengths 12\frac{1}{2} and 13\frac{1}{3}?
    16\frac{1}{6} square unit. Multiply: 12×13=16\frac{1}{2} \times \frac{1}{3} = \frac{1}{6}.
  23. What is the area of a rectangle with side lengths 78\frac{7}{8} and 34\frac{3}{4}?
    2132\frac{21}{32}. Multiply: 78×34=2132\frac{7}{8} \times \frac{3}{4} = \frac{21}{32}.
  24. State the area formula for a rectangle with side lengths aa and bb.
    A=a×bA = a \times b. Area equals length times width for any rectangle.
  25. What is the area of a rectangle with side lengths 2142\frac{1}{4} and 23\frac{2}{3}?
    32\frac{3}{2} square units. Convert 214=942\frac{1}{4} = \frac{9}{4}, then 94×23=1812=32\frac{9}{4} \times \frac{2}{3} = \frac{18}{12} = \frac{3}{2}.
  26. What is the area of a rectangle with side lengths 12\frac{1}{2} and 34\frac{3}{4}?
    38\frac{3}{8} square units. Multiply: 12×34=38\frac{1}{2} \times \frac{3}{4} = \frac{3}{8}.
  27. What is the area of a rectangle with side lengths 23\frac{2}{3} and 38\frac{3}{8}?
    14\frac{1}{4}. Multiply: 23×38=624=14\frac{2}{3} \times \frac{3}{8} = \frac{6}{24} = \frac{1}{4}.
  28. Identify the missing side length if A=16A = \frac{1}{6} and one side is 12\frac{1}{2}.
    13\frac{1}{3}. Divide area by known side: 16÷12=16×2=13\frac{1}{6} \div \frac{1}{2} = \frac{1}{6} \times 2 = \frac{1}{3}.
  29. What is the area of a rectangle with side lengths 2142\frac{1}{4} and 49\frac{4}{9}?
    11. Convert: 214=942\frac{1}{4} = \frac{9}{4}, then 94×49=1\frac{9}{4} \times \frac{4}{9} = 1.
  30. What is the area of a rectangle with side lengths 56\frac{5}{6} and 34\frac{3}{4}?
    58\frac{5}{8} square units. Multiply: 56×34=1524=58\frac{5}{6} \times \frac{3}{4} = \frac{15}{24} = \frac{5}{8}.
  31. How many 14\frac{1}{4} by 13\frac{1}{3} tiles cover a 34\frac{3}{4} by 23\frac{2}{3} rectangle?
    66 tiles. 33 tiles along one side times 22 tiles along the other.
  32. Find the missing side length if A=310A=\frac{3}{10} and one side is 34\frac{3}{4}.
    25\frac{2}{5}. Solve: 34×?=310\frac{3}{4} \times ? = \frac{3}{10}, so ?=310÷34=25? = \frac{3}{10} \div \frac{3}{4} = \frac{2}{5}.
  33. What is the area of a rectangle with side lengths 25\frac{2}{5} and 25\frac{2}{5}?
    425\frac{4}{25} square unit. Multiply: 25×25=425\frac{2}{5} \times \frac{2}{5} = \frac{4}{25}.
  34. What is the area of a rectangle with side lengths 56\frac{5}{6} and 310\frac{3}{10}?
    14\frac{1}{4}. Multiply: 56×310=1560=14\frac{5}{6} \times \frac{3}{10} = \frac{15}{60} = \frac{1}{4}.
  35. What is the area of a rectangle with side lengths 910\frac{9}{10} and 56\frac{5}{6}?
    34\frac{3}{4}. Multiply: 910×56=4560=34\frac{9}{10} \times \frac{5}{6} = \frac{45}{60} = \frac{3}{4}.
  36. Choose the correct statement: Tiling a fractional rectangle gives the same area as doing what operation?
    Multiplying the side lengths: A=l×wA = l \times w. Tiling and multiplication both yield the same area result.
  37. What is the area of one tile with side lengths 14\frac{1}{4} and 13\frac{1}{3}?
    112\frac{1}{12} square unit. Multiply: 14×13=112\frac{1}{4} \times \frac{1}{3} = \frac{1}{12}.
  38. What is the area of one tile that is 15\frac{1}{5} by 17\frac{1}{7}?
    135\frac{1}{35}. Multiply tile dimensions: 15×17=135\frac{1}{5} \times \frac{1}{7} = \frac{1}{35}.
  39. What is the area of a rectangle with side lengths 49\frac{4}{9} and 38\frac{3}{8}?
    16\frac{1}{6} square unit. Multiply: 49×38=1272=16\frac{4}{9} \times \frac{3}{8} = \frac{12}{72} = \frac{1}{6}.
  40. What is the area of a rectangle with side lengths 1121\frac{1}{2} and 23\frac{2}{3}?
    11 square unit. Convert: 112=321\frac{1}{2} = \frac{3}{2}, then 32×23=1\frac{3}{2} \times \frac{2}{3} = 1.
  41. What is the area of a rectangle with side lengths 1112\frac{11}{12} and 611\frac{6}{11}?
    12\frac{1}{2} square unit. Multiply: 1112×611=66132=12\frac{11}{12} \times \frac{6}{11} = \frac{66}{132} = \frac{1}{2}.
  42. State the multiplication rule for fractions used to find rectangle area with fractional sides.
    ab×cd=acbd\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}. Multiply numerators together and denominators together.
  43. What is the area of a rectangle with side lengths 49\frac{4}{9} and 35\frac{3}{5}?
    415\frac{4}{15} square unit. Multiply: 49×35=1245=415\frac{4}{9} \times \frac{3}{5} = \frac{12}{45} = \frac{4}{15}.
  44. How many 17\frac{1}{7}-tall rows fit up a height of 47\frac{4}{7}?
    44 rows. 47÷17=4\frac{4}{7} \div \frac{1}{7} = 4 rows fit exactly.
  45. Find and correct the error: 23×35=56\frac{2}{3} \times \frac{3}{5} = \frac{5}{6}.
    Correct: 23×35=25\frac{2}{3} \times \frac{3}{5} = \frac{2}{5}. The error shows 56\frac{5}{6} instead of correct product 615=25\frac{6}{15} = \frac{2}{5}.
  46. What is the area of a rectangle with side lengths 910\frac{9}{10} and 56\frac{5}{6}?
    34\frac{3}{4} square unit. Multiply: 910×56=4560=34\frac{9}{10} \times \frac{5}{6} = \frac{45}{60} = \frac{3}{4}.
  47. What is the area of a rectangle with side lengths 78\frac{7}{8} and 47\frac{4}{7}?
    12\frac{1}{2} square unit. Multiply: 78×47=2856=12\frac{7}{8} \times \frac{4}{7} = \frac{28}{56} = \frac{1}{2}.
  48. What is the area of a rectangle with side lengths 1112\frac{11}{12} and 311\frac{3}{11}?
    14\frac{1}{4}. Multiply: 1112×311=33132=14\frac{11}{12} \times \frac{3}{11} = \frac{33}{132} = \frac{1}{4}.
  49. How many 14\frac{1}{4}-length segments fit along a side of length 34\frac{3}{4}?
    33. Divide: 34÷14=3\frac{3}{4} \div \frac{1}{4} = 3.

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