Apply Rectangle Area and Perimeter Formulas - 4th Grade Math

  1. Find the missing length ll if P=44P = 44 and w=8w = 8 for a rectangle.
    l=14l = 14. Use P=2l+2wP = 2l + 2w: 44=2l+2(8)44 = 2l + 2(8), so l=14l = 14.
  2. Find the missing side ll if P=44P = 44 yd and w=9w = 9 yd.
    l=13l = 13 yd. From P=2l+2wP = 2l + 2w: 44=2l+2(9)44 = 2l + 2(9), so l=13l = 13 yd.
  3. Find the width when a rectangle has area A=42A = 42 and length l=7l = 7.
    66. Use w=Al=427w = \frac{A}{l} = \frac{42}{7}.
  4. What is the area of a rectangle with l=8l = 8 units and w=5w = 5 units?
    4040 square units. Multiply length times width: 8×5=408 \times 5 = 40.
  5. What is the perimeter of a rectangle with l=6l = 6 and w=6w = 6?
    2424 units. For a square, P=4s=4(6)=24P = 4s = 4(6) = 24 units.
  6. Find the length of a rectangle with perimeter P=34P = 34 and width w=8w = 8.
    99. Use l=34−2(8)2=182=9l = \frac{34 - 2(8)}{2} = \frac{18}{2} = 9.
  7. Which expression gives the perimeter of a rectangle with side lengths ll and ww?
    2(l+w)2(l + w). Factored form of perimeter formula: 2(l+w)=2l+2w2(l + w) = 2l + 2w.
  8. Find the length when a rectangle has area A=36A = 36 and width w=6w = 6.
    66. Use l=Aw=366l = \frac{A}{w} = \frac{36}{6}.
  9. A room is 99 ft long with floor area 7272 ft2^2. What is the width?
    88 ft. Divide area by length: 72÷9=872 \div 9 = 8 ft.
  10. Which expression equals the area of a rectangle with L=6L = 6 and W=11W = 11?
    6×116 \times 11. Area is the product of length and width.
  11. What is the area of a rectangle that is 1212 ft long and 33 ft wide?
    3636 square feet. Multiply length times width: 12×3=3612 \times 3 = 36.
  12. Find WW if P=30P = 30 and L=10L = 10 for a rectangle.
    W=5W = 5. From P=2L+2WP = 2L + 2W: 30=2(10)+2W30 = 2(10) + 2W, so W=5W = 5.
  13. Find and correct the formula error: A=2l+2wA = 2l + 2w is labeled as area for a rectangle.
    Correct: A=l×wA = l \times w. The given formula is for perimeter, not area.
  14. Find the length when a rectangle has perimeter P=24P = 24 and width w=4w = 4.
    88. Use l=242−4=12−4l = \frac{24}{2} - 4 = 12 - 4.
  15. A rectangular garden is 1515 m by 33 m. What is the perimeter in meters?
    3636. Garden perimeter is 2(15)+2(3)=30+6=362(15) + 2(3) = 30 + 6 = 36 m.
  16. What is the missing side length if a rectangle has area AA and length ll?
    w=Alw = \frac{A}{l}. Divide area by length since A=l×wA = l \times w.
  17. A room has area 9696 ft2^2 and length 1212 ft. What is the width?
    88 ft. Rearrange A=l×wA = l \times w: 96÷12=896 \div 12 = 8 ft.
  18. Find the missing width ww if P=30P = 30 and l=10l = 10 for a rectangle.
    w=5w = 5. Use P=2l+2wP = 2l + 2w: 30=2(10)+2w30 = 2(10) + 2w, so w=5w = 5.
  19. A rectangle has P=36P = 36 and w=7w = 7. What is ll?
    l=11l = 11. From P=2l+2wP = 2l + 2w: 36=2l+2(7)36 = 2l + 2(7), so l=11l = 11.
  20. A room has A=63A = 63 square units and L=9L = 9 units. What is the width WW?
    W=7W = 7 units. Divide area by length: 63÷9=763 \div 9 = 7.
  21. Find the missing side ww if A=35A = 35 m2^2 and l=5l = 5 m.
    w=7w = 7 m. Divide area by length: 35÷5=735 \div 5 = 7 m.
  22. What is the perimeter of a rectangle with L=15L = 15 units and W=2W = 2 units?
    3434 units. Apply P=2(15)+2(2)=30+4P = 2(15) + 2(2) = 30 + 4.
  23. What is the missing factor form for finding length when AA and ww are known?
    l=Awl = \frac{A}{w}. Divide area by width since A=l×wA = l \times w.
  24. Find the area of a rectangle with l=8l = 8 and w=6w = 6.
    4848. Apply A=l×w=8×6=48A = l \times w = 8 \times 6 = 48.
  25. Find and correct the formula error: P=L×WP = L \times W is labeled as perimeter.
    Correct perimeter formula: P=2L+2WP = 2L + 2W. The given formula is for area, not perimeter.
  26. A room is 1212 ft long and 1010 ft wide. What is the floor area in square feet?
    120120. Floor area uses A=12×10=120A = 12 \times 10 = 120 sq ft.
  27. Find and correct the formula error: A=2L+2WA = 2L + 2W is labeled as area.
    Correct area formula: A=L×WA = L \times W. The given formula is for perimeter, not area.
  28. Identify the correct unit for area when side lengths are measured in centimeters.
    cm2\text{cm}^2. Area is measured in square units of the side lengths.
  29. Identify the correct unit for area: inches, square inches, or inches per side.
    square inches. Area measures surface in square units.
  30. Find the width of a rectangle with area A=35A = 35 and length l=7l = 7.
    55. Use w=Al=357=5w = \frac{A}{l} = \frac{35}{7} = 5.
  31. Identify the missing factor: If A=36A = 36 and W=4W = 4, what is LL?
    L=9L = 9. Since A=L×WA = L \times W, divide: 36÷4=936 \div 4 = 9.
  32. A rectangle has perimeter 5050 cm and length 1515 cm. What is the width?
    1010 cm. From P=2l+2wP = 2l + 2w: 50=2(15)+2w50 = 2(15) + 2w, so w=10w = 10.
  33. Find LL if P=50P = 50 and W=12W = 12 for a rectangle.
    L=13L = 13. From P=2L+2WP = 2L + 2W: 50=2L+2(12)50 = 2L + 2(12), so L=13L = 13.
  34. Find and correct the error: A student wrote P=l×wP = l \times w for a rectangle.
    Correct: P=2l+2wP = 2l + 2w. Student confused area formula with perimeter formula.
  35. What is the missing length ll if a rectangle has P=18P = 18 and w=4w = 4?
    l=5l = 5. From P=2l+2wP = 2l + 2w: 18=2l+2(4)18 = 2l + 2(4), so l=5l = 5.
  36. Find the width when a rectangle has perimeter P=30P = 30 and length l=10l = 10.
    55. Use w=302−10=15−10w = \frac{30}{2} - 10 = 15 - 10.
  37. What is the missing side length if a rectangle has area AA and width ww?
    l=Awl = \frac{A}{w}. Divide area by width since A=l×wA = l \times w.
  38. State the formula for the area of a rectangle with length ll and width ww.
    A=l×wA = l \times w. Area equals length times width for rectangles.
  39. A picture frame has l=11l = 11 in and w=7w = 7 in. What is the perimeter?
    3636 in. Add all sides: 2(11)+2(7)=22+14=362(11) + 2(7) = 22 + 14 = 36 in.
  40. What is the area of a rectangle with L=12L = 12 units and W=3W = 3 units?
    3636 square units. Apply A=L×W=12×3A = L \times W = 12 \times 3.
  41. Which expression equals the perimeter of a rectangle with L=6L = 6 and W=11W = 11?
    2(6+11)2(6 + 11). Perimeter formula factored: P=2(L+W)P = 2(L + W).
  42. Identify the missing factor: If A=42A = 42 and L=7L = 7, what is WW?
    W=6W = 6. Since A=L×WA = L \times W, divide: 42÷7=642 \div 7 = 6.
  43. What is the perimeter of a rectangle with l=9l = 9 units and w=4w = 4 units?
    2626 units. Add all sides: 2(9)+2(4)=18+8=262(9) + 2(4) = 18 + 8 = 26.
  44. A rectangle has area A=48A = 48. If L=6L = 6, what is WW?
    W=8W = 8. Divide area by length: 48÷6=848 \div 6 = 8.
  45. A rectangle has area A=64A = 64. If l=16l = 16, what is ww?
    44. Solve 64=16×w64 = 16 \times w, so w=4w = 4.
  46. Find the missing length ll if A=63A = 63 and w=7w = 7 for a rectangle.
    l=9l = 9. Divide area by width: 63÷7=963 \div 7 = 9.
  47. What is the perimeter of a rectangle that is 1212 ft long and 33 ft wide?
    3030 feet. Add all sides: 2(12)+2(3)=24+6=302(12) + 2(3) = 24 + 6 = 30.
  48. What is the total area of 22 identical rectangles, each with A=18A = 18 square units?
    3636 square units. Add the areas: 18+18=3618 + 18 = 36 square units.
  49. What is the missing length ll if a rectangle has A=54A = 54 and w=6w = 6?
    l=9l = 9. Divide area by width: 54÷6=954 \div 6 = 9.
  50. State the perimeter formula written as a multiplication expression for a rectangle.
    P=2(l+w)P = 2(l + w). Factor out 2 from the sum of length and width.
  51. State the formula for the perimeter of a rectangle with length ll and width ww.
    P=2l+2wP = 2l + 2w. Add all four sides: two lengths plus two widths.
  52. A rectangle has perimeter P=36P = 36. If W=7W = 7, what is LL?
    L=11L = 11. Solve 36=2L+2(7)36 = 2L + 2(7) to get L=11L = 11.
  53. What is the perimeter of a rectangle with l=9l = 9 and w=4w = 4?
    2626 units. Add all sides: 2(9)+2(4)=18+8=262(9) + 2(4) = 18 + 8 = 26.
  54. Find and correct the formula error: P=l×wP = l \times w is labeled as rectangle perimeter.
    Correct: P=2l+2wP = 2l + 2w. l×wl \times w gives area, not perimeter.
  55. Identify the correct unit for perimeter: square feet or feet.
    feet. Perimeter measures distance in linear units.
  56. Find the area of a 77 by 1010 rectangular garden.
    7070 square units. Multiply length by width: 7×107 \times 10.
  57. Which expression matches the perimeter of a rectangle: l+wl + w or 2(l+w)2(l + w)?
    2(l+w)2(l + w). Perimeter adds all sides, which is 2(l+w)2(l + w).
  58. What is the missing width ww if a rectangle has A=42A = 42 and l=7l = 7?
    w=6w = 6. Divide area by length: 42÷7=642 \div 7 = 6.
  59. Find the perimeter of a rectangle with l=9l = 9 and w=4w = 4.
    2626. Apply P=2(9)+2(4)=18+8=26P = 2(9) + 2(4) = 18 + 8 = 26.
  60. A rectangle has P=28P = 28 units and L=8L = 8 units. What is the width WW?
    W=6W = 6 units. Solve 28=2(8)+2W28 = 2(8) + 2W to get W=6W = 6.
  61. Identify the correct unit for the perimeter of a 66 cm by 22 cm rectangle.
    centimeters (cm\text{cm}). Perimeter is a linear measurement.
  62. Identify the error: A student says the perimeter formula is P=l×wP = l \times w.
    Correct formula: P=2l+2wP = 2l + 2w. Student confused area formula with perimeter formula.
  63. Find and correct the error: A student wrote A=2l+2wA = 2l + 2w for a rectangle.
    Correct: A=l×wA = l \times w. Student confused perimeter formula with area formula.
  64. Identify the correct unit for perimeter when side lengths are measured in centimeters.
    centimeters, cm\text{cm}. Perimeter uses the same linear unit as the sides.
  65. A rectangular rug is 1212 ft by 33 ft. What is its area?
    3636 square feet. Apply area formula: 12×3=3612 \times 3 = 36 square feet.
  66. Identify the correct unit for the area of a 66 cm by 22 cm rectangle.
    square centimeters (cm2\text{cm}^2). Area is measured in square units.
  67. What is the missing width ww if a rectangle has P=30P = 30 and l=10l = 10?
    w=5w = 5. From P=2l+2wP = 2l + 2w: 30=2(10)+2w30 = 2(10) + 2w, so w=5w = 5.
  68. What is the area of a rectangle with l=8l = 8 and w=5w = 5?
    4040 square units. Multiply length times width: 8×5=408 \times 5 = 40.
  69. A garden is 1515 m by 33 m. What is the perimeter in meters?
    36 m36\ \text{m}. Garden perimeter = 2(15)+2(3)2(15) + 2(3) meters.
  70. Identify the missing number: A=6×□A = 6 \times \square and A=48A = 48.
    88. Find the missing factor: 48÷6=848 \div 6 = 8.
  71. Find the length of a rectangle with area A=54A = 54 and width w=6w = 6.
    99. Use l=Aw=546=9l = \frac{A}{w} = \frac{54}{6} = 9.
  72. A rectangle has perimeter P=24P = 24 and width w=5w = 5. What is the length ll?
    77. Solve 24=2l+2(5)24 = 2l + 2(5), so 2l=142l = 14 and l=7l = 7.
  73. Find the perimeter of a 77 by 1010 rectangular garden.
    3434 units. Add all sides: 2(7)+2(10)=14+202(7) + 2(10) = 14 + 20.
  74. What is the area of a rectangle with l=11l = 11 and w=1w = 1?
    1111 square units. Multiply length times width: 11×1=1111 \times 1 = 11.
  75. Find the missing width ww if A=48A = 48 and l=6l = 6 for a rectangle.
    w=8w = 8. Divide area by length: 48÷6=848 \div 6 = 8.
  76. A room is 1212 ft by 99 ft. What is the area of the floor in ft2\text{ft}^2?
    108 ft2108\ \text{ft}^2. Floor area = 12×912 \times 9 square feet.
  77. Identify the correct unit for perimeter when side lengths are measured in meters.
    m\text{m}. Perimeter uses the same linear unit as the sides.
  78. Find the width of a rectangle with perimeter P=30P = 30 and length l=9l = 9.
    66. Use w=30−2(9)2=122=6w = \frac{30 - 2(9)}{2} = \frac{12}{2} = 6.
  79. A rectangular garden is 77 m by 22 m. What is its perimeter?
    1818 meters. Apply perimeter formula: 2(7)+2(2)=182(7) + 2(2) = 18 meters.
  80. Identify the correct unit for area when side lengths are measured in meters.
    square meters, m2\text{m}^2. Area units are squared since we multiply two lengths.
  81. State the perimeter formula written using parentheses for a rectangle with length ll and width ww.
    P=2(l+w)P = 2(l + w). Factor out 2 from the sum of length and width.
  82. A rectangle has A=72A = 72 and w=9w = 9. What is ll?
    l=8l = 8. Divide area by width: 72÷9=872 \div 9 = 8.
  83. What is the missing factor form for finding width when AA and ll are known?
    w=Alw = \frac{A}{l}. Divide area by length since A=l×wA = l \times w.

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