Use Area Models for Distribution - 3rd Grade Math

  1. What is the area using distribution: 7(2+1)7(2+1)?
    2121. 7(2+1)=7(3)=217(2+1)=7(3)=21 or 7⋅2+7⋅1=14+7=217\cdot^2+7\cdot^1=14+7=21.
  2. Identify the correct distributed form of 8(4+3)8(4+3).
    8⋅4+8⋅38\cdot 4+8\cdot 3. Distribute 88 to both 44 and 33.
  3. Identify the missing term: 6(4+2)=6×4+  ‾6(4+2)=6\times 4+\underline{\ \ }.
    6×26\times 2. Distribute 66 to both 44 and 22.
  4. Find and correct the error: 4(2+7)=4⋅2+74(2+7)=4\cdot 2+7.
    Correct: 4(2+7)=4⋅2+4⋅74(2+7)=4\cdot 2+4\cdot 7. Must distribute 4 to both 2 and 7.
  5. A rectangle has height 44 and widths 33 and 66. What is the total area?
    3636 square units. 4×(3+6)=4×9=364 \times (3 + 6) = 4 \times 9 = 36.
  6. What property does the area model show in a(b+c)=ab+aca(b+c)=ab+ac?
    The distributive property. Shows that multiplying a sum equals the sum of products.
  7. What does acac represent in an area model with height aa and right width cc?
    Area of the right smaller rectangle. Product of height and right width gives right area.
  8. What does abab represent in an area model split into widths bb and cc with height aa?
    Area of the aa by bb part. The left section has width bb and height aa.
  9. What is the area using distribution: 5(8+2)5(8+2)?
    5050. 5(8+2)=5(10)=505(8+2)=5(10)=50 or 5⋅8+5⋅2=40+10=505\cdot^8+5\cdot^2=40+10=50.
  10. Identify the correct area statement for a rectangle of height 22 and total width 9+19+1.
    2(9+1)=2×9+2×12(9+1)=2\times 9+2\times 1. Shows distributive property for this rectangle.
  11. What is the value of 7(2+6)7(2+6) using the area model sum 7×2+7×67\times 2+7\times 6?
    5656. 7×2+7×6=14+42=567 \times 2 + 7 \times 6 = 14 + 42 = 56.
  12. What is the value of the missing factor: 6(3+4)=6⋅3+6⋅‾6(3+4)=6\cdot 3+6\cdot \underline{\hspace{1cm}}?
    44. Distribute 66 to both addends: 6⋅3+6⋅46\cdot^3+6\cdot^4.
  13. A rectangle has height 99 and total width 5+25+2. What is its area?
    6363 square units. 9×(5+2)=9×7=639 \times (5 + 2) = 9 \times 7 = 63.
  14. Find the total area: a rectangle is 22 units by 6+36+3 units. What is the area?
    1818 square units. 2(6+3)=2(9)=182(6+3)=2(9)=18 square units.
  15. What is the total area if a=6a=6, b=2b=2, and c=5c=5 for a rectangle with sides aa and b+cb+c?
    4242 square units. a(b+c)=6(2+5)=6(7)=42a(b+c)=6(2+5)=6(7)=42 square units.
  16. What is the area of a rectangle with side lengths aa and b+cb+c?
    a(b+c)a(b+c) square units. Multiply height by total width to find area.
  17. What is the area using distribution: 3(5+2)3(5+2)?
    2121. 3(5+2)=3(7)=213(5+2)=3(7)=21 or 3⋅5+3⋅2=15+6=213\cdot^5+3\cdot^2=15+6=21.
  18. What is the area of a rectangle with side lengths aa and b+cb+c written as a sum of two products?
    ab+acab+ac. The rectangle splits into two parts with areas abab and acac.
  19. Identify the missing term: a(b+c)=ab+‾a(b+c)=ab+\underline{\hspace{1cm}}.
    acac. Distribute aa to both bb and cc.
  20. What is 8(10+1)8(10+1) written using the distributive property as a sum?
    8⋅10+8⋅18\cdot 10+8\cdot 1. Multiply 8 by each addend: 8⋅108\cdot 10 and 8⋅18\cdot 1.
  21. What does abab represent in an area model with height aa and left width bb?
    Area of the left smaller rectangle. Product of height and left width gives left area.
  22. What does acac represent in an area model split into widths bb and cc with height aa?
    Area of the aa by cc part. The right section has width cc and height aa.
  23. Which equation matches a rectangle tiled into two parts: a×ba\times b tiles and a×ca\times c tiles?
    a(b+c)=ab+aca(b+c)=ab+ac. Total tiles equal sum of tiles in each section.
  24. What is the missing side length: if a(b+c)=a⋅9a(b+c)=a\cdot 9 and b=4b=4, what is cc?
    c=5c=5. Since b+c=9b+c=9 and b=4b=4, then c=9−4=5c=9-4=5.
  25. Identify the missing term: a(b+c)=‾+aca(b+c)=\underline{\hspace{1cm}}+ac.
    abab. Distribute aa to both terms in parentheses.
  26. Which expression matches an area model with height aa and widths bb and cc added together?
    ab+acab+ac. Same as splitting a rectangle into two parts.
  27. Find the total area: a rectangle is 55 units by 7+17+1 units. What is the area?
    4040 square units. 5(7+1)=5(8)=405(7+1)=5(8)=40 square units.
  28. What is the area using distribution: 4(6+3)4(6+3)?
    3636. 4(6+3)=4(9)=364(6+3)=4(9)=36 or 4⋅6+4⋅3=24+12=364\cdot^6+4\cdot^3=24+12=36.
  29. What is the missing expression: a(b+c)=‾+aca(b+c)=\underline{\hspace{1cm}}+ac?
    abab. Distributing aa to both bb and cc gives ab+acab+ac.
  30. Which expression matches the area model with height aa and widths bb and cc: a(b+c)a(b+c) or a+b+ca+b+c?
    a(b+c)a(b+c). Area equals height times total width.
  31. What is the value of 6(7+3)6(7+3) using 6×7+6×36\times 7+6\times 3?
    6060. 6×7+6×3=42+18=606 \times 7 + 6 \times 3 = 42 + 18 = 60.
  32. Find a(b+c)a(b+c) when a=3a=3, b=8b=8, and c=1c=1.
    2727. 3×(8+1)=3×9=273 \times (8 + 1) = 3 \times 9 = 27.
  33. What is 5(9+6)5(9+6) written using the distributive property as a sum?
    5⋅9+5⋅65\cdot 9+5\cdot 6. Multiply 5 by each addend: 5⋅95\cdot 9 and 5⋅65\cdot 6.
  34. What is the value of 5(3+4)5(3+4) using 5×3+5×45\times 3+5\times 4?
    3535. 5×3+5×4=15+20=355 \times 3 + 5 \times 4 = 15 + 20 = 35.
  35. What is 7(3+5)7(3+5) written using the distributive property as a sum?
    7⋅3+7⋅57\cdot 3+7\cdot 5. Multiply 7 by each addend: 7⋅37\cdot 3 and 7⋅57\cdot 5.
  36. Find the area using distribution: 7(5+2)7(5+2).
    7⋅5+7⋅2=497\cdot 5+7\cdot 2=49. 7⋅5=357\cdot 5=35 and 7⋅2=147\cdot 2=14, sum is 4949.
  37. What is the area of a rectangle with side lengths aa and b+cb+c written as one product?
    a(b+c)a(b+c). The total width is b+cb+c, multiplied by height aa.
  38. What is the value of 8(5+1)8(5+1) using 8×5+8×18\times 5+8\times 1?
    4848. 8×5+8×1=40+8=488 \times 5 + 8 \times 1 = 40 + 8 = 48.
  39. What is the value of the missing factor: 9(1+5)=9⋅‾+9⋅59(1+5)=9\cdot \underline{\hspace{1cm}}+9\cdot 5?
    11. Distribute 99 to both addends: 9⋅1+9⋅59\cdot^1+9\cdot^5.
  40. What is the value of 3(10+2)3(10+2) using the distributive property?
    3636. 3×10+3×2=30+6=363 \times 10 + 3 \times 2 = 30 + 6 = 36.
  41. What unit is used to count area when using tiling with 1×11\times 1 squares?
    Square units. Each tile is one square unit.
  42. What is 6(4+2)6(4+2) written using the distributive property as a sum?
    6⋅4+6⋅26\cdot 4+6\cdot 2. Multiply 6 by each addend: 6⋅46\cdot 4 and 6⋅26\cdot 2.
  43. Find ab+acab+ac when a=4a=4, b=5b=5, and c=2c=2.
    2828. 4×5+4×2=20+8=284 \times 5 + 4 \times 2 = 20 + 8 = 28.
  44. Find the area using distribution: 9(4+3)9(4+3).
    9⋅4+9⋅3=639\cdot 4+9\cdot 3=63. 9⋅4=369\cdot 4=36 and 9⋅3=279\cdot 3=27, sum is 6363.
  45. Find the total area: one rectangle is 3×83\times 8 and the other is 3×23\times 2.
    3⋅8+3⋅2=303\cdot 8+3\cdot 2=30. Add areas: 24+6=3024+6=30 square units.
  46. What property does the area model show when a(b+c)=ab+aca(b+c)=ab+ac?
    The distributive property of multiplication over addition. Shows that multiplying a number by a sum equals the sum of the products.
  47. What is the sum of the two sub-areas when a rectangle is split into widths bb and cc with height aa?
    ab+acab+ac square units. Add the areas of both sub-rectangles.
  48. Find the total area: one rectangle is 4×64\times 6 and the other is 4×34\times 3.
    4⋅6+4⋅3=364\cdot 6+4\cdot 3=36. Add areas: 24+12=3624+12=36 square units.
  49. What does b+cb+c represent on an area model rectangle split into two parts labeled bb and cc?
    The total width. Sum of the two width segments.
  50. What equation shows splitting width b+cb+c into bb and cc for a rectangle of height aa?
    a(b+c)=ab+aca(b+c)=ab+ac. Shows area of whole equals sum of parts.
  51. What is the missing expression: a(b+c)=ab+‾a(b+c)=ab+\underline{\hspace{1cm}}?
    acac. Distributing aa to both bb and cc gives ab+acab+ac.

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