Solve Perimeter and Area Problems - 3rd Grade Math

  1. Choose the rectangle with the same perimeter as 33 by 77: 22 by 88 or 44 by 66.
    22 by 88. Both have P=20P = 20; 33 by 77 gives P=20P = 20, 22 by 88 gives P=20P = 20.
  2. Find the missing side xx if a triangle has perimeter P=17P = 17 and sides 66, 55, and xx.
    x=6x = 6. From 17=6+5+x17 = 6 + 5 + x, solve: 17=11+x17 = 11 + x, so x=6x = 6.
  3. Find the missing side length if P=18P = 18 and the other sides are 44, 55, and 66.
    33. Subtract known sides from perimeter: 18−4−5−6=318 - 4 - 5 - 6 = 3.
  4. Which value is the perimeter of a rectangle with l=6l = 6 and w=2w = 2: 1616 or 1212?
    1616. Calculate P=2(6)+2(2)=12+4=16P = 2(6) + 2(2) = 12 + 4 = 16.
  5. What is the perimeter of a rectangle with l=9l = 9 and w=4w = 4?
    2626. Use P=2l+2w=2(9)+2(4)=18+8P = 2l + 2w = 2(9) + 2(4) = 18 + 8.
  6. What is the perimeter of a rectangle with l=8l = 8 and w=3w = 3?
    2222. Using P=2(8)+2(3)=16+6=22P = 2(8) + 2(3) = 16 + 6 = 22.
  7. Find the missing length ll if a rectangle has perimeter 2424 and width 44.
    l=8l = 8. Use 24=2l+2(4)24 = 2l + 2(4), so 2l=162l = 16, thus l=8l = 8.
  8. Two rectangles both have area 1212: 33 by 44 and 22 by 66. What are their perimeters, in order?
    1414 and 1616. 33 by 44 has P=14P = 14; 22 by 66 has P=16P = 16.
  9. What is the perimeter of a triangle with side lengths 33, 44, and 55?
    1212. Add all three sides: 3+4+5=123 + 4 + 5 = 12.
  10. Identify the area of a 5×15 \times 1 rectangle and a 3×33 \times 3 rectangle with the same perimeter 1212.
    55 and 99. 5×1=55 × 1 = 5 and 3×3=93 × 3 = 9; both rectangles have perimeter 12.
  11. Identify two rectangles with the same area 2424 but different perimeters: 6×46 \times 4 and 8×38 \times 3.
    Perimeters: 2020 and 2222 units. 6×46 \times 4 has P=20P = 20; 8×38 \times 3 has P=22P = 22.
  12. Identify the perimeter of a shape with sides 88 m, 33 m, 88 m, and 33 m.
    2222 m. Add all sides: 8+3+8+3=228 + 3 + 8 + 3 = 22.
  13. What is the perimeter of a square with side length 77 inches?
    2828 inches. Use P=4(7)=28P = 4(7) = 28 for a square.
  14. What is the perimeter of a square with side length s=6s = 6?
    2424. Using P=4(6)=24P = 4(6) = 24 for a square.
  15. What is the perimeter of a square with side length 77?
    2828. Multiply side length by 4: 7×4=287 × 4 = 28.
  16. What is the perimeter of a pentagon with side lengths 22, 22, 33, 33, and 44?
    1414 units. Add all five sides: 2+2+3+3+4=142 + 2 + 3 + 3 + 4 = 14.
  17. Which statement is true: Same perimeter always means same area, or it can mean different areas?
    Same perimeter can mean different areas. Rectangles can have equal perimeters but different shapes/areas.
  18. State the formula for the perimeter of a rectangle with length ll and width ww.
    P=2l+2wP = 2l + 2w. Add length and width twice each to get the distance around.
  19. Identify the area of a rectangle with l=6l = 6 and w=2w = 2.
    1212. Area equals length times width: 6×2=126 × 2 = 12.
  20. State the formula for the perimeter of a polygon with side lengths s1,s2,…,sns_1, s_2, \dots, s_n.
    P=s1+s2+⋯+snP = s_1 + s_2 + \cdots + s_n. Add all side lengths to find the perimeter.
  21. Identify the perimeter of a pentagon with side lengths 22, 33, 22, 44, and 33.
    1414. Sum all five sides: 2+3+2+4+3=142 + 3 + 2 + 4 + 3 = 14.
  22. Find the side length ss of a square with perimeter P=28P = 28.
    s=7s = 7. From 28=4s28 = 4s, divide both sides by 4 to get s=7s = 7.
  23. Identify the area of a rectangle with l=4l = 4 and w=3w = 3.
    1212. Multiply length by width: 4×3=124 × 3 = 12.
  24. State the formula for the perimeter of a square with side length ss.
    P=4sP = 4s. Multiply side length by 4 since all sides are equal.
  25. What is the perimeter of a rectangle with l=9l = 9 and w=2w = 2?
    2222. Using P=2(9)+2(2)=18+4=22P = 2(9) + 2(2) = 18 + 4 = 22.
  26. What is the perimeter of a triangle with side lengths 44, 55, and 66?
    1515. Sum all three sides: 4+5+6=154 + 5 + 6 = 15.
  27. What is the perimeter of a 6×26 \times 2 rectangle (length 66, width 22)?
    1616. Calculate P=2(6)+2(2)=12+4=16P = 2(6) + 2(2) = 12 + 4 = 16.
  28. Find the unknown length ll if a rectangle has P=22P = 22 and w=4w = 4.
    l=7l = 7. From 22=2l+2(4)22 = 2l + 2(4), solve: 22=2l+822 = 2l + 8, so 2l=142l = 14.
  29. State the rule for finding the perimeter of any polygon from its side lengths.
    Add all side lengths: P=s1+s2+⋯P = s_1 + s_2 + \cdots. Perimeter is the sum of all side lengths.
  30. Which rectangle has perimeter 1212 and larger area: 5×15 \times 1 or 3×33 \times 3?
    3×33 \times 3. 3×33 × 3 has area 9, which is larger than 5×15 × 1's area of 5.
  31. Which rectangle has the larger perimeter: 22 by 99 or 33 by 66?
    22 by 99. 22 by 99 has P=22P = 22; 33 by 66 has P=18P = 18.
  32. What is the area of a rectangle with l=6l = 6 and w=4w = 4 (for comparing area vs. perimeter)?
    2424 square units. Area equals length times width: A=6×4=24A = 6 \times 4 = 24.
  33. What is the perimeter of a rectangle with area 1616 and side lengths 22 and 88?
    2020 units. Use P=2(2)+2(8)=4+16=20P = 2(2) + 2(8) = 4 + 16 = 20.
  34. Find the missing width ww if a rectangle has perimeter 3030 and length 1010.
    w=5w = 5. Use 30=2(10)+2w30 = 2(10) + 2w, so 2w=102w = 10, thus w=5w = 5.
  35. What is the perimeter of a pentagon with side lengths 33, 33, 44, 44, and 66?
    2020. Sum all five sides: 3+3+4+4+6=203 + 3 + 4 + 4 + 6 = 20.
  36. Find the missing side length xx if a triangle has perimeter 2020 and sides 66, 77, and xx.
    x=7x = 7. Subtract known sides from perimeter: 20−6−7=720 - 6 - 7 = 7.
  37. Find and correct the mistake: A student says P=l+wP = l + w for a rectangle.
    Correct: P=2l+2wP = 2l + 2w. Student forgot to multiply by 2; must count all 4 sides.
  38. What is the perimeter of a rectangle with side lengths 88, 33, 88, and 33?
    2222. Add all four sides: 8+3+8+3=228 + 3 + 8 + 3 = 22.
  39. Find the unknown width ww if a rectangle has P=30P = 30 and l=10l = 10.
    w=5w = 5. From 30=2(10)+2w30 = 2(10) + 2w, solve: 30=20+2w30 = 20 + 2w, so 2w=102w = 10.
  40. What is the perimeter of a rectangle with l=9l = 9 cm and w=4w = 4 cm?
    2626 cm. Use P=2(9)+2(4)=18+8=26P = 2(9) + 2(4) = 18 + 8 = 26.
  41. Which statement is true: same perimeter means same area, or same perimeter can have different areas?
    Same perimeter can have different areas. Rectangles can share perimeter but have different dimensions and areas.
  42. Find the unknown side xx if a rectangle has perimeter P=18P = 18, l=5l = 5, and w=xw = x.
    x=4x = 4. From 18=2(5)+2x18 = 2(5) + 2x, solve: 18=10+2x18 = 10 + 2x, so x=4x = 4.
  43. What is the perimeter of a 4×34 \times 3 rectangle (length 44, width 33)?
    1414. Calculate P=2(4)+2(3)=8+6=14P = 2(4) + 2(3) = 8 + 6 = 14.
  44. Which rectangle has area 1212 but a different perimeter than 4×34 \times 3: 6×26 \times 2 or 3×43 \times 4?
    6×26 \times 2. 6×26 × 2 has area 12 and perimeter 16, different from 4×34 × 3's perimeter 14.
  45. Which statement is true: same area means same perimeter, or same area can have different perimeters?
    Same area can have different perimeters. Rectangles can share area but have different dimensions and perimeters.
  46. Identify two rectangles with the same perimeter 2020 but different areas: 6×46 \times 4 and 7×37 \times 3.
    Areas: 2424 and 2121 square units. 6×4=246 \times 4 = 24 and 7×3=217 \times 3 = 21 with same P=20P = 20.
  47. Find the missing side xx if a quadrilateral has perimeter 2525 and sides 66, 88, 55, and xx.
    x=6x = 6. Subtract known sides: 25−6−8−5=625 - 6 - 8 - 5 = 6.
  48. Which expression represents the perimeter of a rectangle with sides aa and bb?
    2a+2b2a + 2b. Rectangle perimeter formula with different variable names.
  49. What is the perimeter of a polygon with side lengths 33, 55, 44, and 66 units?
    1818 units. Add all sides: 3+5+4+6=183 + 5 + 4 + 6 = 18.
  50. What is the perimeter of a square with side length ss?
    P=4sP = 4s. A square has 4 equal sides, so multiply side length by 4.
  51. Find the unknown side ss of a square if the perimeter is P=36P = 36.
    s=9s = 9. Divide perimeter by 4 to find side: 36÷4=936 ÷ 4 = 9.
  52. Which statement is true: Same area always means same perimeter, or it can mean different perimeters?
    Same area can mean different perimeters. Rectangles can have equal areas but different shapes/perimeters.
  53. Find the missing side xx if a quadrilateral has perimeter P=24P = 24 and sides 77, 55, 66, and xx.
    x=6x = 6. From 24=7+5+6+x24 = 7 + 5 + 6 + x, solve: 24=18+x24 = 18 + x, so x=6x = 6.
  54. What are the areas of rectangles 22 by 88 and 44 by 66 (same perimeter), in order?
    1616 and 2424. 2×8=162 \times 8 = 16 and 4×6=244 \times 6 = 24 show different areas.

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