Use the theorem for the Definite Integral as the Area of a Region.
is continuous and nonnegative on the closed interval [
], then the area of the region bounded by the graph of
–axis, and the vertical lines
is given by
Here, the interval of the bounded region is [0, 2].
So, the area,
of the bounded region is the definite integral of
from 0 to 2.
Multiply and divide the integrand by 2.
Use a formula of Integration Involving Inverse Hyperbolic Functions.
be a differentiable function of
Evaluate the antiderivative at the limits of integration.
Therefore, the area of the bounded region is about 5.237 units
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