### All High School Math Resources

## Example Questions

### Example Question #1 : How To Find The Area Of A Circle

A circle with a diameter of 6” sits inside a circle with a radius of 8”. What is the area of the interstitial space between the two circles?

**Possible Answers:**

28π in2

55π in2

72π in2

25π in2

7π in2

**Correct answer:**

55π in2

The area of a circle is πr^{2}.

The diameter of the first circle = 6” so radius of the first circle = 3” so the area = π * 3^{2} = 9π in^{2}

The radius of the second circle = 8” so the area = π * 8^{2} = 64π in^{2}

The area of the interstitial space = area of the first circle – area of the second circle.

Area = 64π in^{2 }- 9π in^{2} = 55π in^{2}

### Example Question #71 : Circles

If the radius of a circle is tripled, and the new area is 144π what was the diameter of the original circle?

**Possible Answers:**

6

8

4

7

12

**Correct answer:**

8

The area of a circle is A=πr^{2}. Since the radius was tripled 144π =π(3r)^{2}. Divide by π and then take the square root of both sides of the equal sign to get 12=3r, and then r=4. The diameter (d) is equal to twice the radius so d= 2(4) = 8.

### Example Question #1 : Radius

If the radius of Circle A is three times the radius of Circle B, what is the ratio of the area of Circle A to the area of Circle B?

**Possible Answers:**

9

3

6

15

12

**Correct answer:**

9

We know that the equation for the area of a circle is π r^{2}. To solve this problem, we pick radii for Circles A and B, making sure that Circle A’s radius is three times Circle B’s radius, as the problem specifies. Then we will divide the resulting areas of the two circles. For example, if we say that Circle A has radius 6 and Circle B has radius 2, then the ratio of the area of Circle A to B is: (π 6^{2})/(π 2^{2}) = 36π/4π. From here, the π's cancel out, leaving 36/4 = 9.

### Example Question #11 : How To Find The Area Of A Circle

- A circle is inscribed inside a 10 by 10 square. What is the area of the circle?

**Possible Answers:**

10π

50π

25π

100π

40π

**Correct answer:**

25π

Area of a circle = A = πr^{2}

R = 1/2d = ½(10) = 5

A = 5^{2}π = 25π

### Example Question #11 : How To Find The Area Of A Circle

A square has an area of 1089 in^{2}. If a circle is inscribed within the square, what is its area?

**Possible Answers:**

16.5 in^{2}

33 in^{2}

272.25π in^{2}

1089π in^{2}

33π in^{2}

**Correct answer:**

272.25π in^{2}

The diameter of the circle is the length of a side of the square. Therefore, first solve for the length of the square's sides. The area of the square is:

A = s^{2} or 1089 = s^{2}. Taking the square root of both sides, we get: s = 33.

Now, based on this, we know that 2r = 33 or r = 16.5. The area of the circle is πr^{2} or π16.5^{2} = 272.25π.

### Example Question #211 : High School Math

A square has an area of 32 in^{2}. If a circle is inscribed within the square, what is its area?

**Possible Answers:**

4√2 in^{2}

32π in^{2}

8π in^{2}

16π in^{2}

2√2 in^{2}

**Correct answer:**

8π in^{2}

The diameter of the circle is the length of a side of the square. Therefore, first solve for the length of the square's sides. The area of the square is:

A = s^{2} or 32 = s^{2}. Taking the square root of both sides, we get: s = √32 = √(2^{5}) = 4√2.

Now, based on this, we know that 2r = 4√2 or r = 2√2. The area of the circle is πr^{2} or π(2√2)^{2} = 4 * 2π = 8π.

### Example Question #1 : Know And Use The Formulas For The Area And Circumference Of A Circle: Ccss.Math.Content.7.G.B.4

A manufacturer makes wooden circles out of square blocks of wood. If the wood costs $0.25 per square inch, what is the minimum waste cost possible for cutting a circle with a radius of 44 in.?

**Possible Answers:**

5808 dollars

1936π dollars

1936 dollars

7744 – 1936π dollars

1936 – 484π dollars

**Correct answer:**

1936 – 484π dollars

The smallest block from which a circle could be made would be a square that perfectly matches the diameter of the given circle. (This is presuming we have perfectly calibrated equipment.) Such a square would have dimensions equal to the diameter of the circle, meaning it would have sides of 88 inches for our problem. Its total area would be 88 * 88 or 7744 in^{2}.

Now, the waste amount would be the "corners" remaining after the circle was cut. The area of the circle is πr^{2} or π * 44^{2} = 1936π in^{2}. Therefore, the area remaining would be 7744 – 1936π. The cost of the waste would be 0.25 * (7744 – 1936π). This is not an option for our answers, so let us simplify a bit. We can factor out a common 4 from our subtraction. This would give us: 0.25 * 4 * (1936 – 484π). Since 0.25 is equal to 1/4, 0.25 * 4 = 1. Therefore, our final answer is: 1936 – 484π dollars.

### Example Question #212 : High School Math

A manufacturer makes wooden circles out of square blocks of wood. If the wood costs $0.20 per square inch, what is the minimum waste cost possible for cutting a circle with a radius of 25 in.?

**Possible Answers:**

2500 - 625π dollars

625 - 25π dollars

500 dollars

500 - 125π dollars

625 dollars

**Correct answer:**

500 - 125π dollars

The smallest block from which a circle could be made would be a square that perfectly matches the diameter of the given circle. (This is presuming we have perfectly calibrated equipment.) Such a square would have dimensions equal to the diameter of the circle, meaning it would have sides of 50 inches for our problem. Its total area would be 50 * 50 or 2500 in^{2}.

Now, the waste amount would be the "corners" remaining after the circle was cut. The area of the circle is πr^{2} or π * 25^{2} = 625π in^{2}. Therefore, the area remaining would be 2500 - 625π. The cost of the waste would be 0.2 * (2500 – 625π). This is not an option for our answers, so let us simplify a bit. We can factor out a common 5 from our subtraction. This would give us: 0.2 * 5 * (500 – 125π). Since 0.2 is equal to 1/5, 0.2 * 625 = 125. Therefore, our final answer is: 500 – 125π dollars.

### Example Question #551 : Geometry

**Possible Answers:**

20*π*

100*π*

10*π*

25*π*

50*π*

**Correct answer:**

50*π*

### Example Question #61 : Circles

A circle with diameter of length is inscribed in a square. Which of the following is equivalent to the area inside of the square, but outside of the circle?

**Possible Answers:**

**Correct answer:**

In order to find the area that is inside the square but outside the circle, we will need to subtract the area of the circle from the area of the square. The area of a circle is equal to . However, since we are given the length of the diameter, we will need to solve for the radius in terms of the diameter. Because the diameter of a circle is twice the length of its radius, we can write the following equation and solve for :

Divide both sides by 2.

We will now substitute this into the formula for the area of the circle.

area of circle =

We next will need to find the area of the square. Because the circle is inscribed in the square, the diameter of the circle is equal to the length of the circle's side. In other words, the square has side lengths equal to d. The area of any square is equal to the square of its side length. Therefore, the area of the square is .

area of square =

Lastly, we will subtract the area of the circle from the area of the square.

difference in areas =

We will rewrite so that its denominator is 4.

difference in areas =

The answer is .

Certified Tutor