### All Common Core: High School - Geometry Resources

## Example Questions

### Example Question #1 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line parallel to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute -7 for and 10 for

After plugging them in, we get.

Now we solve for

### Example Question #52 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line parallel to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute 7 for and 5 for

After plugging them in, we get.

Now we solve for

### Example Question #2 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line perpendicular to and goes through the point

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute -10 for and 10 for

After plugging them in, we get.

Now we solve for

### Example Question #54 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line perpendicular to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute 1 for and -2 for

After plugging them in, we get.

Now we solve for

### Example Question #1 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line parallel to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute -4 for and -6 for

After plugging them in, we get.

Now we solve for

### Example Question #1 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line perpendicular to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute -1 for and -9 for

After plugging them in, we get.

Now we solve for

In slope intercept form, find the equation of the line perpendicular to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

So

Then we substitute 2 for and -5 for

After plugging them in, we get.

Now we solve for

In slope intercept form, find the equation of the line perpendicular to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

So

Then we substitute 7 for and -5 for

After plugging them in, we get.

Now we solve for

In slope intercept form, find the equation of the line parallel to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

So

Then we substitute -5 for and 6 for

After plugging them in, we get.

Now we solve for

In slope intercept form, find the equation of the line perpendicular to and goes through the point .

**Possible Answers:**

**Correct answer:**

First step is to recall slope intercept form.

Where is the slope, and is a point on the line.

So

Then we substitute -5 for and -4 for

After plugging them in, we get.

Now we solve for