# Common Core: High School - Geometry : Prove Slope Criteria for Parallel and Perpendicular Lines: CCSS.Math.Content.HSG-GPE.B.5

## Example Questions

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### Example Question #51 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line parallel to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute -7 for  and 10 for

After plugging them in, we get.

Now we solve for

### Example Question #52 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line parallel to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute 7 for  and 5 for

After plugging them in, we get.

Now we solve for

### Example Question #53 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line perpendicular to  and goes through the point

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute -10 for  and 10 for

After plugging them in, we get.

Now we solve for

### Example Question #54 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line perpendicular to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute 1 for  and -2 for

After plugging them in, we get.

Now we solve for

### Example Question #5 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line parallel to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute -4 for  and -6 for

After plugging them in, we get.

Now we solve for

### Example Question #55 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line perpendicular to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute -1 for  and -9 for

After plugging them in, we get.

Now we solve for

### Example Question #56 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line perpendicular to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute 2 for  and -5 for

After plugging them in, we get.

Now we solve for

### Example Question #8 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line perpendicular to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute 7 for  and -5 for

After plugging them in, we get.

Now we solve for

### Example Question #57 : Expressing Geometric Properties With Equations

In slope intercept form, find the equation of the line parallel to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is parallel, our slope () is going to be the same as the original equation.

So

Then we substitute -5 for  and 6 for

After plugging them in, we get.

Now we solve for

### Example Question #1 : Prove Slope Criteria For Parallel And Perpendicular Lines: Ccss.Math.Content.Hsg Gpe.B.5

In slope intercept form, find the equation of the line perpendicular to  and goes through the point .

Possible Answers:

Correct answer:

Explanation:

First step is to recall slope intercept form.

Where  is the slope, and  is a point on the line.

Since we want a line that is perpendicular, our slope () is going to be the negative reciprocal of the original equation.

So

Then we substitute -5 for  and -4 for

After plugging them in, we get.

Now we solve for

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