Common Core: 7th Grade Math : Ratios & Proportional Relationships

Study concepts, example questions & explanations for Common Core: 7th Grade Math

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Example Questions

Example Question #41 : Compute Unit Rates Associated With Ratios Of Fractions: Ccss.Math.Content.7.Rp.A.1

Kendall can clean  of a house in  of an hour. If she continues this rate, how much of the house can Kendall clean per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the house, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Kendall can clean  of the house per hour. 

Example Question #42 : Grade 7

Kylie can clean  of a house in  of an hour. If she continues this rate, how much of the house can Kylie clean per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the house, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Kylie can clean  of the house per hour. 

Example Question #43 : Grade 7

Greg can complete  of his homework in  of an hour. If he continues this rate, how much of his homework can Greg complete per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have amount of homework, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Greg can complete  of his homework per hour. 

Example Question #44 : Grade 7

Aubtin can complete  of his homework in  of an hour. If he continues this rate, how much of his homework can Aubtin complete per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have amount of homework, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Aubtin can complete  of his homework per hour. 

Example Question #45 : Grade 7

Tim can complete  of his homework in  of an hour. If he continues this rate, how much of his homework can Tim complete per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have amount of homework, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Tim can complete  of his homework per hour. 

Example Question #46 : Grade 7

James can complete  of his homework in  of an hour. If he continues this rate, how much of his homework can James complete per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have amount of homework, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

James can complete  of his homework per hour. 

Example Question #47 : Grade 7

Michael can complete  of his homework in  of an hour. If he continues this rate, how much of his homework can Michael complete per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have amount of homework, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Michael can complete  of his homework per hour. 

Example Question #48 : Grade 7

A baker can decorate  of a wedding cake in  of an hour. If the baker continues this rate, how much of the wedding cake can he decorate per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the cake decorated, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The baker can decorate  of the wedding cake per hour. 

Example Question #49 : Grade 7

A baker can decorate  of a wedding cake in  of an hour. If the baker continues this rate, how much of the wedding cake can he decorate per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the cake decorated, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The baker can decorate  of the wedding cake per hour. 

Example Question #41 : Grade 7

A baker can decorate  of a wedding cake in  of an hour. If the baker continues this rate, how much of the wedding cake can he decorate per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the cake decorated, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The baker can decorate  of the wedding cake per hour. 

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