Common Core: 7th Grade Math : Compute Unit Rates Associated with Ratios of Fractions: CCSS.Math.Content.7.RP.A.1

Study concepts, example questions & explanations for Common Core: 7th Grade Math

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Example Questions

Example Question #61 : Grade 7

A landscaper can mow  of a yard in  of an hour. If he continues at this rate, how many yards can the landscaper mow per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The landscaper can mow  yards per hour. 

Example Question #62 : Grade 7

A landscaper can mow  of a yard in  of an hour. If he continues at this rate, how many yards can the landscaper mow per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have yards, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The landscaper can mow  yard per hour. 

Example Question #63 : Grade 7

A janitor can clean  of a stadium in  of an hour. If he continues this rate, how much of the stadium can he clean per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the stadium, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The janitor can clean  of the stadium per hour. 

Example Question #61 : Compute Unit Rates Associated With Ratios Of Fractions: Ccss.Math.Content.7.Rp.A.1

A janitor can clean  of a stadium in  of an hour. If he continues this rate, how much of the stadium can he clean per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the stadium, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The janitor can clean  of the stadium per hour. 

Example Question #65 : Grade 7

A janitor can clean  of a stadium in  of an hour. If he continues this rate, how much of the stadium can he clean per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the stadium, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The janitor can clean  of the stadium per hour. 

Example Question #61 : Grade 7

A janitor can clean  of a stadium in  of an hour. If he continues this rate, how much of the stadium can he clean per hour? 

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the stadium, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

The janitor can clean  of the stadium per hour. 

Example Question #67 : Grade 7

Hannah loves to shop. She can shop in  of the mall in  of an hour. If she continues at this rate, how much of the mall can she shop per hour?

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the mall, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Hannah can shop in  of the mall per hour. 

Example Question #61 : Grade 7

Hannah loves to shop. She can shop in  of the mall in  of an hour. If she continues at this rate, how much of the mall can she shop per hour?

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the mall, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Hannah can shop in  of the mall per hour. 

Example Question #69 : Grade 7

Hannah loves to shop. She can shop in  of the mall in  of an hour. If she continues at this rate, how much of the mall can she shop per hour?

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the mall, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Hannah can shop in  of the mall per hour. 

Example Question #61 : Compute Unit Rates Associated With Ratios Of Fractions: Ccss.Math.Content.7.Rp.A.1

Hannah loves to shop. She can shop in  of the mall in  of an hour. If she continues at this rate, how much of the mall can she shop per hour?

Possible Answers:

Correct answer:

Explanation:

The phrase "per hour" gives us a clue that we are going to divide. In this problem, we can replace the word "per" with a division sign; therefore, we will have the portion of the mall, , divided by hours, :

Remember that when we divide fractions, we can simply multiply by the reciprocal of the denominator to solve. 

Therefore:

Hannah can shop in  of the mall per hour. 

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