### All Calculus 2 Resources

## Example Questions

### Example Question #1 : Limits And Continuity

Find the values of and so that is everywhere differentiable.

**Possible Answers:**

**Correct answer:**

If a function is to be everywhere differentiable, then it must also be continuous everywhere. This implies that the one sided limits must be equal: .

Next, the one sided limits of the derivative must also be equal. That is, .

Now we have two missing variables and two equations. Set up a system and solve by elimination or substitution.

### Example Question #1 : Continuity In Terms Of Limits

The graph above is a sketch of the function . For what intervals is continuous?

**Possible Answers:**

**Correct answer:**

For a function to be continuous at a point , must exist and .

This is true for all values of except and .

Therefore, the interval of continuity is .

### Example Question #2 : Limits And Continuity

Suppose that are continuous functions on . Which of the following is FALSE?

**Possible Answers:**

may not be well defined for all real numbers.

All of the others are true.

is well defined for all real numbers, and is continuous on .

has either an absolute maximum, absolute minimum, or both.

exists for any real number .

**Correct answer:**

has either an absolute maximum, absolute minimum, or both.

In order to show this statement is false, we must provide one counterexample.

For example, let . Both of these are continuous functions (Their graphes are connected with no "jumps" or "breaks"). Then , but does not have an absolute maximum, or mimimum.

### Example Question #2 : Continuity In Terms Of Limits

Consider the piecewise function:

What is ?

**Possible Answers:**

Limit does not exist.

**Correct answer:**

Limit does not exist.

The piecewise function

indicates that is one when is less than five, and is zero if the variable is greater than five. At , there is a hole at the end of the split.

The limit does not indicate whether we want to find the limit from the left or right, which means that it is necessary to check the limit from the left and right. From the left to right, the limit approaches 1 as approaches negative five. From the right, the limit approaches zero as approaches negative five.

Since the limits do not coincide, the limit does not exist for .

### Example Question #3 : Continuity In Terms Of Limits

Consider the function .

Which of the following statements are true about this function?

I.

II.

III.

**Possible Answers:**

III only

II only

I and II

I and III

**Correct answer:**

I and II

For a function to be continuous at a particular point, the limit of the function at that point must be equal to the value of the function at that point.

First, notice that

.

This means that the function is continuous everywhere.

Next, we must compute the limit. Factor and simplify f(x) to help with the calculation of the limit.

Thus, the limit as x approaches three exists and is equal to , so I and II are true statements.

### Example Question #3 : Limits And Continuity

Determine whether or not the function is continuous at the given value of .

at

**Possible Answers:**

Function is NOT continuous; the limit of the function does not exist.

Function is NOT continuous; the limit of the function does not exist and function is not defined at the given value.

Function is NOT continuous; function is not defined at the given value.

Function is continuous

**Correct answer:**

Function is continuous

The definition of continuity at a point is

.

Since is in the interval of the domain of the function, we see

Also, since the function approaches as approaches from the left and the right, we see that

.

Since

the function is continuous at .

### Example Question #4 : Limits And Continuity

Given the above graph of , over which of the following intervals is continuous?

**Possible Answers:**

None of the above

**Correct answer:**

For a function to be continuous at a given point , it must meet the following two conditions:

1.) The point must exist, and

2.) .

Examining the above graph, is continuous at every possible value of except for . Thus, is continuous on the interval .

### Example Question #5 : Limits And Continuity

Given the above graph of , over which of the following intervals is continuous?

**Possible Answers:**

**Correct answer:**

For a function to be continuous at a given point , it must meet the following two conditions:

1.) The point must exist, and

2.) .

Examining the above graph, is continuous at every possible value of except for and . Thus, is continuous on the interval .

### Example Question #6 : Limits And Continuity

Given the above graph of , over which of the following intervals is continuous?

**Possible Answers:**

None of the above

**Correct answer:**

For a function to be continuous at a given point , it must meet the following two conditions:

1.) The point must exist, and

2.) .

Examining the above graph, is continuous at every possible value of except for and . Thus, is continuous on the interval .

### Example Question #7 : Limits And Continuity

Given the above graph of , over which of the following intervals is continuous?

**Possible Answers:**

None of the above

**Correct answer:**

For a function to be continuous at a given point , it must meet the following two conditions:

1.) The point must exist, and

2.) .

Examining the above graph, is continuous at every possible value of except for . Thus, is continuous on the interval .

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