### All Algebra 1 Resources

## Example Questions

### Example Question #39 : How To Find The Solution For A System Of Equations

In the standard coordinate plane, *slope-intercept form* is defined for a straight line as , where is the slope and is the point on the line where .

Give the coordinates at which the following lines intersect:

**Possible Answers:**

The two lines do not intersect.

**Correct answer:**

The two lines do not intersect.

The first step is to set the two equations equal to each other, since at the point of intersection, they will be. To do this more easily, convert each equation into slope-intercept form.

**First equation:**

** Already in slope-intercept form**

**Second equation:**

** State equation**

**Add to both sides.**

** Divide both sides by .**

At this point, note that both equations have idential slopes: for both equations, but different -intercepts. Thus, the lines are parallel, and will never touch. We can stop here, but let's prove our theory with algebra by setting the equations equal to one another:

**Set your equations.**

** Subtract from both sides.**

** No solution.**

Thus, there is no solution to this equation, and the lines are parallel.

### Example Question #40 : How To Find The Solution For A System Of Equations

In the standard coordinate plane, *slope-intercept form* is defined for a straight line as , where is the slope and is the point on the line where .

Give the coordinates at which the following lines intersect:

**Possible Answers:**

The two lines do not intersect.

**Correct answer:**

The first step is to set the two equations equal to each other, since at the point of intersection, they will be. To do this more easily, convert each equation into slope-intercept form.

**First equation:**

** State equation**

**Add to both sides.**

**Divide both sides by .**

**Second equation:**

** State equation**

**Symmetric**** Property of Identity**

Now, since each equation equals , the equations also equal each other (for the point of intersection). By solving for , therefore, we can

**State equation.**

**Add to both sides.**

**Subtract from both sides.**

** Divide both sides by (or multiply both sides by ).**

So, the -coordinate of our intersection is . To find the -coordinate, plug this result back into one of the original equations.

**State your chosen equation.**

**Substitute the value of .**

**Multiply.**

**Subtract.**

So, the coordinates where the two lines intersect are .

### Example Question #41 : How To Find The Solution For A System Of Equations

In the standard coordinate plane, *slope-intercept form* is defined for a straight line as , where is the slope and is the point on the line where .

Give the coordinates at which the following lines intersect:

**Possible Answers:**

The two lines do not intersect.

**Correct answer:**

The first step is to set the two equations equal to each other, since at the point of intersection, they will be. To do this more easily, convert each equation into slope-intercept form.

**First equation:**

** State equation**

**Multiply both sides by .**

**Second equation:**

** State equation**

**Subtract from both sides.**

** Divide both sides by .**

**Rearrange (symmetric property of equality).**

Now, since each equation equals , the equations also equal each other (for the point of intersection). By solving for , therefore, we can

**State equation.**

**Add to both sides.**

**Add to both sides.**

** Divide both sides by .**

So, the -coordinate of our intersection is . To find the -coordinate, plug this result back into one of the original equations.

**State your chosen equation.**

**Substitute the value of .**

**Distribute****.**

** Simplify.**

So, the coordinates where the two lines intersect are .

### Example Question #191 : Systems Of Equations

*slope-intercept form* is defined for a straight line as , where is the slope and is the point on the line where .

Give the coordinates at which the following lines intersect:

**Possible Answers:**

The lines are identical.

**Correct answer:**

The lines are identical.

**First equation:**

** State equation**

**Divide both sides by .**

** Rearrange the right side to match slope-intercept form.**

**Second equation:**

** This equation is already in slope-intercept form.**

Notice how the two equations are identical? This means the lines do not intersect at one point -- they intersect at *all* points, and are identical lines.

### Example Question #192 : Systems Of Equations

Solve the following system of equations.

**Possible Answers:**

no solution

**Correct answer:**

Let's use the method of substution to solve this. First we need to get one variable in terms of the other variable. Look at the 2nd equation and isolate x:

Moving y to the right side:

Now plug in this value of x into the first equation and solve for y:

Now plug y back into to either of the oringial two equations and solve for x:

Our answer is:

### Example Question #193 : Systems Of Equations

Solve for the value of *p* in the following system of equations:

**Possible Answers:**

**Correct answer:**

This system of equations simplifies very nicely if one begins by isolating the variable *q* in the second equation. Isolating *q *in the second equation yields: . Now substitute this expression for *q* into the first equation. This results in: . Now distribute the one-third term outside the brackets to obtain: . This expression will simplify quite simply to: .

### Example Question #194 : Systems Of Equations

Solve this system of equations:

**Possible Answers:**

**Correct answer:**

We can rewrite the first equation as:

If we substitute this new value for into the second equation we get:

Simplify.

Combine like terms

Solve for

Now substitute this value into either of the original equations:

### Example Question #195 : Systems Of Equations

If

and

,

then what is the value of

?

**Possible Answers:**

**Correct answer:**

While substitution is a plausible way to solve this problem, it does not provide the most effecient solution. Instead, begin by subtracting the first equation from the second equation in a manner similar to the "elimination" method used by many students.

This subtraction will result in

.

Now, simply divide this result by 3 to obtain

.

This result, indicates that the correct answer choice is 15. This problem is an excellent example of a time trap. The use of substitution would require use of fractions or time consuming conversions to decimals. If, however, the test taker identifies the route between the original two functions and the desired function of unkown value, then this problem becomes much quicker.

### Example Question #196 : Systems Of Equations

If

;

;

and

,

then which of the following MUST be true?

**Possible Answers:**

None of the above: Not enough information exists to prove any of these statements.

**Correct answer:**

First notice that in this system of equations, there are four unkown variables, but only three independent equations. Therefore, we know the system is indeterminate and so substitution/elimination will not work. The answer, however, is NOT "None of the above". The explanation is below:

Note that the third equation is extraneous information. Begin by look at the second equation, . This equation tells us that at least one of the variables (x, y, or z) must equal zero in order for the overall expression to equal zero. Now, look at the first equation . This equation indicates that NONE of the variables (r,z, nor x) are equal to zero, as the overall expression does NOT equal zero. Realize that "y" is the only variable that exists in the second expression, but does not exist in the first expression.

**Therefore, we can definitively state that **

### Example Question #197 : Systems Of Equations

Find the solution to this system of equations:

**Possible Answers:**

None of these

**Correct answer:**

To find the solution we will multiply by some number to cancel out one variable and then solve for the variable that is left over. This is called the "elimination" method. You may choose to eliminate either variable, but it is prudent to choose the variable that is easier to cancel.

1)

2)

Multiply equation 1 by -2:

Add new equation 1 to equation 2:

The result is

Solve for y:

Now solve for x by plugging in the value for y (we can choose either original equation):

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