### All Algebra 1 Resources

## Example Questions

### Example Question #51 : How To Find The Solution For A System Of Equations

Find the solution to this system of equations:

**Possible Answers:**

None of these

**Correct answer:**

To find the solution we will multiply by some number to cancel out one variable and then solve for the variable that is left over. This is called the "elimination" method. You may choose to eliminate either variable, but it is prudent to choose the variable that is easier to cancel.

1)

2)

Multiply equation 1 by -2:

Add new equation 1 to equation 2:

The result is

Solve for y:

Now solve for x by plugging in the value for y (we can choose either original equation):

### Example Question #52 : How To Find The Solution For A System Of Equations

Find the solution set for this system of equations:

**Possible Answers:**

None of these

**Correct answer:**

To solve this system of equations, multiply each equation by an integer that would allow us to cancel one variable. We then substitute that value back into either original equation to find the other variable. In this case we will cancel the x variable by multiplying each equation by 3 and 4 respectively.

1)

2)

Multiply equation 1 by 3 and equation 2 by 4:

Add the new equations:

The result is

Solve for y:

Now substitute this value back into equation 1:

### Example Question #51 : How To Find The Solution For A System Of Equations

Give the solution to the system of equations below.

**Possible Answers:**

No solution

**Correct answer:**

Solve the second equation for , allowing us to solve using the substitution method.

Substitute for in the first equation, and solve for .

Now, substitute for in either equation; we will choose the second. This allows us to solve for .

Now we can write the solution in the notation , or .

### Example Question #1 : Solve Systems Of Two Linear Equations: Ccss.Math.Content.8.Ee.C.8b

Solve this system of equations for :

**Possible Answers:**

None of the other choices are correct.

**Correct answer:**

Multiply the bottom equation by , then add to the top equation:

Divide both sides by

### Example Question #221 : Grade 8

Solve the following system of equations:

**Possible Answers:**

no solution

infinitely many solutions

**Correct answer:**

When we add the two equations, the variables cancel leaving us with:

Solving for we get:

We can then substitute our value for into one of the original equations and solve for :

### Example Question #2451 : Algebra 1

Solve the following system of equations.

**Possible Answers:**

**Correct answer:**

We are given

We can solve this by using the substitution method. Notice that you can plug from the first equation into the second equation and then get

Add to both sides

Add 9 to both sides

Divide both sides by 5

So . We can use this value to find y by using either equation. In this case, I'll use .

So the solution is

### Example Question #1 : Solve Problems Leading To Two Linear Equations: Ccss.Math.Content.8.Ee.C.8c

Adult tickets to the zoo sell for ; child tickets sell for . On a given day, the zoo sold tickets and raised in admissions. How many adult tickets were sold?

**Possible Answers:**

**Correct answer:**

Let be the number of adult tickets sold. Then the number of child tickets sold is .

The amount of money raised from adult tickets is ; the amount of money raised from child tickets is . The sum of these money amounts is , so the amount of money raised can be defined by the following equation:

To find the number of adult tickets sold, solve for :

adult tickets were sold.

### Example Question #5 : Solve Problems Leading To Two Linear Equations: Ccss.Math.Content.8.Ee.C.8c

Solve the following story problem:

Jack and Aaron go to the sporting goods store. Jack buys a glove for and wiffle bats for each. Jack has left over. Aaron spends all his money on hats for each and jerseys. Aaron started with more than Jack. How much does one jersey cost?

**Possible Answers:**

**Correct answer:**

Let's call "" the cost of one jersey (this is the value we want to find)

Let's call the amount of money Jack starts with ""

Let's call the amount of money Aaron starts with ""

We know Jack buys a glove for and bats for each, and then has left over after. Thus:

simplifying, so Jack started with

We know Aaron buys hats for each and jerseys (unknown cost "") and spends all his money.

The last important piece of information from the problem is Aaron starts with dollars more than Jack. So:

From before we know:

Plugging in:

so Aaron started with

Finally we plug into our original equation for A and solve for x:

Thus one jersey costs

### Example Question #2453 : Algebra 1

Solve for only:

**Possible Answers:**

**Correct answer:**

Use the elimination process to determine the value of .

Subtract the second equation with the first equation. This will eliminate the x-variable in order to find the y-variable.

The equation becomes:

Use this value and substitute into either the first or second equation and solve for the x-variable.

Let's select the first equation and solve for .

Add six on both sides.

The result will be the same if we substitute into the second equation.

The answer is:

### Example Question #2461 : Algebra 1

Solve only for given the two equations:

**Possible Answers:**

**Correct answer:**

In order to solve for , multiply the first equation by four in order to eliminate the fractions in front of the coefficients.

The first equation becomes:

The second equation remains the same:

Subtract the second equation with the first equation:

The result is:

Divide by two on both sides.

Simplify both sides.

The answer is:

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