### All ACT Math Resources

## Example Questions

### Example Question #74 : Act Math

Given a right triangle with a leg length of and a hypotenuse length of , what is the height of the triangle?

**Possible Answers:**

**Correct answer:**

1. Use the pythagorean theorem with and :

2. Solve for :

(Notice that this right triangle is also a triangle.)

### Example Question #75 : Act Math

A ladder is leaning against a wall. If the bottom of the ladder touches the ground from the base of the wall, approximately (to the nearest whole number) how far is the top of the ladder from the base of the wall?

**Possible Answers:**

**Correct answer:**

To answer this, we first need to understand that we are trying to find the leg of a right triangle. The ladder, when leaned against the wall, forms a right triangle where the ladder is the hypotenuse, the wall is one leg, and the ground between the ladder and the wall is the other leg.

To find how high up the ladder touches the wall, we use the Pythagorean Theorem, which is:

is the length of the hypotenuse (the ladder itself), is the distance of the ladder base from the wall, and is how high the ladder touches on the wall.

We then rearrange to solve for one of the legs by subtracting from both sides.

We can now plug in our values of 10 for the hypotenuse and one of our legs (in this case, )

We can then take the square root of this equation to get an answer for

The question asked us to approximate, so we must round to the nearest whole number. To do this, we round a number up one place if the last digit is a 5, 6, 7, 8, or 9, and we round it down if the last digit is a 1, 2, 3, or 4. Therefore:

Therefore, our answer is .

### Example Question #76 : Act Math

Right triangle has sides that are integers, and an area of . Which of the following could not be the height of ?

**Possible Answers:**

**Correct answer:**

The formula for the area of a triangle is , where is the length and is the height of the triangle. In this case, we know that , which means . Since we are told that the sides are integers, this means that must consist of two factors of . Since is the only number choice not a factor of , it is the only answer that could not meet the requirements.

### Example Question #81 : Act Math

Find the height of a right triangle given a base of and hypotenuse of .

**Possible Answers:**

**Correct answer:**

To solve, simply realize this is one of our special right triangles, . Thus, our answer is . If you forgot this, you can use the Pythagorean Theorem.

### Example Question #1 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem

If and , how long is side ?

**Possible Answers:**

Not enough information to solve

**Correct answer:**

This problem is solved using the Pythagorean theorem . In this formula and are the legs of the right triangle while is the hypotenuse.

Using the labels of our triangle we have:

### Example Question #2 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem

If one of the short sides of a 45-45-90 triangle equals 5, how long is the hypotenuse?

**Possible Answers:**

√10

√15

5√2

5

*π*

**Correct answer:**

5√2

Using the Pythagorean theorem, *x*^{2} + *y*^{2} = *h*^{2}. And since it is a 45-45-90 triangle the two short sides are equal. Therefore 5^{2} + 5^{2} = *h*^{2 }. Multiplied out 25 + 25 = *h*^{2}.

Therefore *h*^{2} = 50, so *h* = √50 = √2 * √25 or 5√2.

### Example Question #3 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem

The height of a right circular cylinder is 10 inches and the diameter of its base is 6 inches. What is the distance from a point on the edge of the base to the center of the entire cylinder?

**Possible Answers:**

√(43)/2

None of the other answers

3π/4

√(34)

4π/5

**Correct answer:**

√(34)

The best thing to do here is to draw diagram and draw the appropiate triangle for what is being asked. It does not matter where you place your point on the base because any point will produce the same result. We know that the center of the base of the cylinder is 3 inches away from the base (6/2). We also know that the center of the cylinder is 5 inches from the base of the cylinder (10/2). So we have a right triangle with a height of 5 inches and a base of 3 inches. So using the Pythagorean Theorem 3^{2 }+ 5^{2 }= c^{2}. 34 = c^{2}, c = √(34).

### Example Question #4 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem

A right triangle with sides A, B, C and respective angles a, b, c has the following measurements.

Side A = 3in. Side B = 4in. What is the length of side C?

**Possible Answers:**

25

9

5

7

6

**Correct answer:**

5

The correct answer is 5. The pythagorean theorem states that a^{2 }+ b^{2 }= c^{2}. So in this case 3^{2 }+ 4^{2 }= C^{2}. So C^{2 }= 25 and C = 5. This is also an example of the common 3-4-5 triangle.

### Example Question #5 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem

The lengths of the three sides of a right triangle form a set of consecutive even integers when arranged from least to greatest. If the second largest side has a length of x, then which of the following equations could be used to solve for x?

**Possible Answers:**

(x + 2)^{2} + (x – 2)^{2} = x^{2}

(x – 2) + x = (x + 2)

(x – 2)^{2} + x^{2} = (x + 2)^{2}

x ^{2} + (x + 2)^{2} = (x + 4)^{2}

(x – 1)^{2} + x^{2} = (x + 1)^{2}

**Correct answer:**

(x – 2)^{2} + x^{2} = (x + 2)^{2}

We are told that the lengths form a series of consecutive even integers. Because even integers are two units apart, the side lengths must differ by two. In other words, the largest side length is two greater than the second largest, and the second largest length is two greater than the smallest length.

The second largest length is equal to x. The second largest length must thus be two less than the largest length. We could represent the largest length as x + 2.

Similarly, the second largest length is two larger than the smallest length, which we could thus represent as x – 2.

To summarize, the lengths of the triangle (in terms of x) are x – 2, x, and x + 2.

In order to solve for x, we can make use of the fact that the triangle is a right triangle. If we apply the Pythagorean Theorem, we can set up an equation that could be used to solve for x. The Pythagorean Theorem states that if a and b are the lengths of the legs of the triangle, and c is the length of the hypotenuse, then the following is true:

a^{2} + b^{2} = c^{2}

In this particular case, the two legs of our triangle are x – 2 and x, since the legs are the two smallest sides; therefore, we can say that a = x – 2, and b = x. Lastly, we can say c = x + 2, since x + 2 is the length of the hypotenuse. Subsituting these values for a, b, and c into the Pythagorean Theorem yields the following:

(x – 2)^{2} + x^{2} = (x + 2)^{2}

The answer is (x – 2)^{2} + x^{2} = (x + 2)^{2}.

### Example Question #6 : How To Find The Length Of The Hypotenuse Of A Right Triangle : Pythagorean Theorem

What is the hypotenuse of a right triangle with sides 5 and 8?

**Possible Answers:**

8√13

5√4

12

√89

15

**Correct answer:**

√89

Because this is a right triangle, we can use the Pythagorean Theorem which says *a*^{2} + *b*^{2} = *c*^{2}, or the squares of the two sides of a right triangle must equal the square of the hypotenuse. Here we have *a* = 5 and *b* = 8.

*a*^{2} + *b*^{2} = *c*^{2}

5^{2} + 8^{2} = *c*^{2}

25 + 64 = *c*^{2}

89 = *c*^{2}

*c* = √89

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