# ACT Math : How to find the solution to a quadratic equation

## Example Questions

### Example Question #11 : How To Find The Solution To A Quadratic Equation

Two consecutive positive multiples of three have a product of . What is the sum of the two numbers?

Explanation:

Let  be defined as the lower number, and  as the greater number.

We know that the first number times the second is , so the equation to solve becomes .

Distributing the gives us a polynomial, which we can solve by factoring.

and

The question tells us that the integers are positive; therefore, .

If , and the second number is , then the second number is .

The sum of these numbers is .

### Example Question #2042 : Act Math

Find the solutions of this quadratic equation:

4y3 - 4y2 = 8y

2, 4

1, 2

–1, 2

–1, –2

–2, 4

–1, 2

Explanation:

4y3 - 4y2 = 8y

Divide by y and set equal to zero.

4y2 - 4y – 8 = 0

(2y + 2)(2y – 4) = 0

2y + 2 = 0

2y = –2

y = –1

2y – 4 = 0

2y = 4

y = 2

### Example Question #11 : How To Find The Solution To A Quadratic Equation

Which of the following is a solution to:

Explanation:

You may use the quadratic formula (where ), which yields two answers,  and .

Since the only solution that appears in the answer list is , we choose .

### Example Question #552 : Algebra

2x + y+ xy+ y = x

If y = 1, what is x?

3

–1

0

2

1

–1

Explanation:

Plug in y = 1. Then solve for x.

2x + yxyy = x

2x + 1 + x + 1 = x

3x + 2 = x

2x = -2

x = -1

### Example Question #25 : Quadratic Equations

What are the -intercept(s) of the following quadratic function?

and

and

and

and

and

Explanation:

-intercepts will occur when . This yields the equation

We need to use the quadratic formula where ,  and .

Plugging in our values:

Simplifying:

Simplifying:

Simplifying:

Finally:

### Example Question #281 : Equations / Inequalities

The length of a rectangular piece of land is two feet more than three times its width. If the area of the land is , what is the width of that piece of land?

Explanation:

The area of a rectangle is the product of its length by its width, which we know to be equal to  in our problem. We also know that the length is equal to , where  represents the width of the land. Therefore, we can write the following equation:

Distributing the  outside the parentheses, we get:

Subtracting  from each side of the equation, we get:

We get a quadratic equation, and since there is no factor of  and  that adds up to , we use the quadratic formula to solve this equation.

We can first calculate the discriminant (i.e. the part under the square root)

We replace that value in the quadratic formula, solving both the positive version of the formula (on the left) and the negative version of the formula (on the right):

Breaking down the square root:

We can pull two of the twos out of the square root and place a  outside of it:

We can then multiply the  and the :

At this point, we can reduce the equations, since each of the component parts of their right sides has a factor of :

Since width is a positive value, the answer is:

The width of the piece of land is approximately .

### Example Question #1 : Quadratic Equation

Solve for x: x2 + 4x = 5

-1

-5 or 1

-1 or 5

-5

-5 or 1

Explanation:

Solve by factoring.  First get everything into the form Ax2 + Bx + C = 0:

x2 + 4x - 5 = 0

Then factor: (x + 5) (x - 1) = 0

Solve each multiple separately for 0:

X + 5 = 0; x = -5

x - 1 = 0; x = 1

Therefore, x is either -5 or 1

### Example Question #1 : Quadratic Equation

Solve for x: (x2 – x) / (x – 1) = 1

x = 2

x = -2

x = 1

x = -1

No solution

No solution

Explanation:

Begin by multiplying both sides by (x – 1):

x2 – x = x – 1

Solve as a quadratic equation: x2 – 2x + 1 = 0

Factor the left: (x – 1)(x – 1) = 0

Therefore,  x = 1.

However, notice that in the original equation, a value of 1 for x would place a 0 in the denominator.  Therefore, there is no solution.

### Example Question #1 : Quadratic Equation

A farmer has  of fence, and wants to fence in his sheep. He wants to build a rectangular pen with one side formed by the side of his barn. He wants the area of the pen to be . Which of the following is a possible dimension for the side opposite the barn?

Explanation:

Set up two equations from the given information:

and .

Substitute into the second equation:

Multiply through by .

Divide by 2:

We can factor this:

Thus .

Note that this is not the side opposite the barn. We need to solve for  in both cases, getting .

24 does not appear in the choices, so  is the only possible correct answer.

### Example Question #161 : Algebra

If f(x) = -x2 + 6x - 5, then which could be the value of a if f(a) = f(1.5)?

1
2.5
4.5
3.5
4
Explanation:

We need to input 1.5 into our function, then we need to input "a" into our function and set these results equal.

f(a) = f(1.5)

f(a) = -(1.5)2 +6(1.5) -5

f(a) = -2.25 + 9 - 5

f(a) = 1.75

-a2 + 6a -5 = 1.75

Multiply both sides by 4, so that we can work with only whole numbers coefficients.

-4a2 + 24a - 20 = 7

Subtract 7 from both sides.

-4a2 + 24a - 27 = 0

Multiply both sides by negative one, just to make more positive coefficients, which are usually easier to work with.

4a2 - 24a + 27 = 0

In order to factor this, we need to mutiply the outer coefficients, which gives us 4(27) = 108. We need to think of two numbers that multiply to give us 108, but add to give us -24. These two numbers are -6 and -18. Now we rewrite the equation as:

4a2 - 6a -18a + 27 = 0

We can now group the first two terms and the last two terms, and then we can factor.

(4a2 - 6a )+(-18a + 27) = 0

2a(2a-3) + -9(2a - 3) = 0

(2a-9)(2a-3) = 0

This means that 2a - 9 =0, or 2a - 3 = 0.

2a - 9 = 0

2a = 9

a = 9/2 = 4.5

2a - 3 = 0

a = 3/2 = 1.5

So a can be either 1.5 or 4.5.

The only answer choice available that could be a is 4.5.