### All SSAT Upper Level Math Resources

## Example Questions

### Example Question #2 : Algebra

Circle A is centered about the origin and has a radius of 5. What is the equation of the line that is tangent to Circle A at the point (–3,4)?

**Possible Answers:**

3*x* – 4*y* = –25

3*x* – 4*y* = –1

–3*x* + 4*y* = 1

3*x* + 4*y* = 7

**Correct answer:**

3*x* – 4*y* = –25

The line must be perpendicular to the radius at the point (–3,4). The slope of the radius is given by

The radius has endpoints (–3,4) and the center of the circle (0,0), so its slope is –4/3.

The slope of the tangent line must be perpendicular to the slope of the radius, so the slope of the line is ¾.

The equation of the line is *y* – 4 = (3/4)(*x* – (–3))

Rearranging gives us: 3*x* – 4*y* = -25

### Example Question #1 : How To Find The Equation Of A Tangent Line

Find the equation of a tangent line at point if the function is .

**Possible Answers:**

**Correct answer:**

To find the slope of the tangent line, it is necessary to determine the slope of the function.

The function is already in the slope-intercept form, , and .

Substitute the slope and the given point into the slope-intercept equation.

Substitute the known slope and the y-intercept to the slope-intercept form.

### All SSAT Upper Level Math Resources

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