All SAT II Math I Resources
Example Question #1 : Surface Area
A circular swimming pool has diameter 32 meters and depth meters throughout. Which of the following expressions gives the total area of the inside of the pool, in square meters?
None of the other responses is correct.
The bottom of the pool is a circle with diameter 32, and, subsequently, radius half this, or 16; its area is
The side of the pool is the lateral surface of a cylinder with radius 16 and height ; the area of this is
The area of the inside of the pool is the sum of these two, or
Example Question #2 : Surface Area
A circular swimming pool at an apartment complex has diameter 50 feet and depth six feet throughout.
The apartment manager needs to get the interior of the swimming pool painted. The paint she wants to use covers 350 square feet per gallon. How many one-gallon cans of paint will she need to purchase?
The correct answer is not given among the other responses.
The pool can be seen as a cylinder with depth (or height) six feet and a base with diameter 50 feet - and radius half this, or 25 feet.
The bottom of the pool - the base of the cylinder - is a circle with radius 25 feet, so its area is
Its side - the lateral face of the cylinder - has area
Their sum - the total area to be painted - is square feet. Since one gallon of paint covers 350 square feet, divide:
Eight cans of paint and part of a ninth will be required, so the correct response is nine.
Example Question #3 : Surface Area
Figure not drawn to scale.
Find the surface area of the cylinder above.
In order to find the surface area of a cylinder, you need to find the surface areas of the circles that are the top and bottom of the cylinder (2 x pi x radius2) and add it to the surface are of the rectangle that is the side of the cylinder (diameter x height).
The surface area of the cylinder is 94.25 in2
Example Question #4 : Surface Area
Figure not drawn to scale
What is the surface area of the sphere above?
In order to find the surface area of a sphere, you must use the equation below:
The surface area of the sphere is 615.75 yd2
Example Question #1 : Solid Geometry
The formula for the surface area of a cone is:
where represents the radius of the cone base and represents the slant height of the cone.
Plugging in our values, we get:
Example Question #2 : Solid Geometry
The surface area of cone is . If the radius of the base of the cone is , what is the height of the cone?
To figure out , we must use the equation for the surface area of a cone, , where is the radius of the base of the cone and is the length of the diagonal from the tip of the cone to any point on the base's circumference. We therefore first need to solve for by plugging what we know into the equation:
This equation can be reduced to:
For a normal right angle cone, represents the line from the tip of the cone running along the outside of the cone to a point on the base's circumference. This line represents the hypotenuse of the right triangle formed by the radius and height of the cone. We can therefore solve for using the Pythagorean theorem:
Our is therefore:
The height of cone is therefore
Example Question #3 : Solid Geometry
A circle of radius five is cut into two pieces, and . The larger section is thrown away. The smaller section is curled until the two straight edges meet, and a bottom is made for the cone.
What is the area of the bottom?
When the smaller portion of the circle is curled in, it will make the top of a cone. The circumfrence of the circle on the bottom is (where r is the radius of the circle on the bottom). The circumference of the bottom is also of the circumfrence of the original larger circle, which is (where R is the radius of the original, larger circle)
Therefore we use the circumference formula to solve for our new r:
Substituting this value into the area formula, the area of the small circle becomes:
Example Question #4 : Solid Geometry
A cone has a bottom area of and a height of , what is the surface area of the cone?
The area of the bottom of the cone yields the radius,
The height of the cone is , so the Pythagorean Theorem will give the slant height,
The area of the side of the cone is and adding that to the given as the area of the circle, the surface area comes to
Example Question #5 : Solid Geometry
If the surface area of a right angle cone is , and the distance from the tip of the cone to a point on the edge of the cone's base is , what is the cone's radius?
Solving this problem is going to take knowledge of Algebra, Geometry, and the equation for the surface area of a cone: , where is the radius of the cone's base and is the distance from the tip of the cone to a point along the edge of the cone's base. First, let's substitute what we know in this equation:
We can divide out from every term in the equation to obtain:
We see this equation has taken the form of a quadratic expression, so to solve for we need to find the zeroes by factoring. We therefore need to find factors of that when added equal . In this case, and :
This gives us solutions of and . Since represents the radius of the cone and the radius must be positive, we know that is our only possible answer, and therefore the radius of the cone is .
Example Question #6 : Solid Geometry
For a right circular cone , the radius is and the height of the cone is . What is the surface area of the cone in terms of ?
To solve this problem, we will need to use the formula for finding the surface area of a cone, , where is the length of the diagonal from the circle edge of the cone to the top. Since we are not given s, we must find it by using Pythagorean's Theorem:
is a prime number, so we cannot factor the radical any further. Therefore, our equation for our surface area of becomes:
, which is our final answer.