High School Physics : Understanding Heat and Temperature

Example Questions

Example Question #8 : Heat

The temperature of an ideal gas is raised from  to . If the volume remains constant, what was its initial pressure if the final pressure is

Explanation:

For this problem, use Gay-Lussac's law to set up a direct proportion between pressure and temperature. Note that this law only applies when volume is constant.

Plug in our given values and solve for the initial pressure.

Example Question #1 : Understanding Heat And Temperature

of soup at  cools down to  after . If the specific heat of the soup is , how much energy does the soup release into the room?

Explanation:

The formula for heat energy is:

We are given the initial and final temperatures, mass, and specific heat. Using these values, we can find the heat released. Note that the time is irrelevant to this calculation.

That means that the soup "lost"  of energy. This is the amount that it released into the room. The value is negative for the soup, the source of the heat, but positive for the room, which receives it.

Example Question #2 : Understanding Heat And Temperature

of soup cools down to after . If the specific heat of the soup is , and it released of energy into the room, what was the initial temperature of the soup?

Explanation:

The formula for heat energy is:

We are given the final temperature, mass, specific heat, and heat released. Using these values, we can find the initial temperature. Note that the time is irrelevant to this calculation. Since heat is released from the soup, the net change in the soup's energy is negative. Since the soup is cooling, we expect our answer to be greater than .

Example Question #3 : Understanding Heat And Temperature

of soup at  cools down after . If the specific heat of the soup is , and it released  of energy into the room, what is the final temperature of the soup?

Explanation:

The formula for heat energy is:

We are given the initial temperature, mass, specific heat, and heat released. Using these values, we can find the final temperature. Note that the time is irrelevant to this calculation. Since heat is released from the soup, the net change in the soup's energy is negative. Since the soup is cooling, we expect our answer to be less than .

Example Question #4 : Understanding Heat And Temperature

An ice cube at  melts. As it melts, constant temperature readings are taken and the sample maintains the temperature of  throughout the melting process. Which statement best describes the energy of the system?

Energy is being used to convert the ice to water

We would need to know the mass of the ice cube to draw a conclusion

Energy increases as the sample moves from a solid to a liquid

The form of water has no bearing on the system energy

Energy of the system remains the same

Energy is being used to convert the ice to water

Explanation:

When an object changes phase, it requires energy called "latent heat." In this case, even though the temperature is remaining constant, the energy inside of the ice cube is decreasing as it expends energy to melt.

Example Question #5 : Understanding Heat And Temperature

silver spoon is placed in a  cup of tea. If the spoon has a mass of  and the tea has  of mass, what is the final temperature of the spoon?

Explanation:

The equation for two items reaching a thermal equilibrium is given by describing a heat transfer. The heat removed from one object is equal to the heat added to the other.

We are given the specific heat values of each substance, as well as their masses. We also know the initial temperature of each substance. Use these terms in the equation to solve for the final temperature. Remember that the final temperature will be the same for each substance, since they will be in thermodynamic equilibrium.

Example Question #6 : Understanding Heat And Temperature

A sample of  of water at  is placed in a ceramic mug, which is at . What is the final temperature of the system?

Explanation:

For this question, we must recognize that the system going to end up in equilibrium. That means that:

We are given the initial temperatures, masses, and specific heats of both the water and the ceramic. This will allow us to solve for the final temperature of the system; this value will be equal for both components. Notice that the specific heat given to us in the problem for the ceramic is in terms of kilograms, not grams. Convert to grams.

Example Question #7 : Understanding Heat And Temperature

A  vial of an unknown liquid is . Julie adds  of the same liquid at  to the vial. What is the final temperature?

We need to know the specific heat of the liquid in order to solve.

We need to know the freezing/boiling points of the liquid in order to solve.

Explanation:

The equation for change in temperature is

Plug in our given values.

Notice that the specific heats will cancel out.

Combine like terms.

Example Question #1 : Calculating Heat And Temperature

A disc of copper is dropped into a  glass of water. If the copper was at  and the water was at , what is the new temperature of the mixture?

Explanation:

The relationship between mass and temperature, when two masses are mixed together, is:

Using the given values for the mass and specific heat of each compound, we can solve for the final temperature.

We need to work to isolate the final temperature.

Distribute into the parenthesis using multiplication.

Combine like terms.