### All GMAT Math Resources

## Example Questions

### Example Question #1 : Calculating The Perimeter Of A Polygon

What is the perimeter of a hexagon?

1) Each side measures 10 cm

2) The hexagon is regular.

**Possible Answers:**

EACH statement ALONE is sufficient.

Statements 1 and 2 TOGETHER are not sufficient.

Statement 2 ALONE is sufficient, but Statement 1 alone is not sufficient.

Statement 1 ALONE is sufficient, but Statement 2 alone is not sufficient.

BOTH statements TOGETHER are sufficient, but neither statement ALONE is sufficient.

**Correct answer:**

Statement 1 ALONE is sufficient, but Statement 2 alone is not sufficient.

The perimeter is the sum of the measures of the sidelengths.

Knowing that the hexagon is regular only tells you the six sides are congruent; without the measure of any side, this does not help you.

Knowing only that each of the six sides measures 10 cm is by itself enough to calculate the perimeter to be

.

The answer is that Statement 1 is sufficient, but not Statement 2.

### Example Question #2 : Calculating The Perimeter Of A Polygon

Note: Figure NOT drawn to scale

What is the perimeter of the above figure?

Assume all angles shown in the figure are right angles.

**Possible Answers:**

Not enough information is given to answer the question.

**Correct answer:**

This figure can be seen as a smaller rectangle cut out of a larger one; refer to the diagram below.

We can fill in the missing sidelengths using the fact that a rectangle has congruent opposite sides. Once this is done, we can add the lengths of the sides to get the perimeter:

feet.

### Example Question #3 : Calculating The Perimeter Of A Polygon

What is the perimeter of a rectangle with a length of and a width of ?

**Possible Answers:**

**Correct answer:**

The perimeter of any figure is the sum of the lengths of its sides. Since we have a rectangle with a length of and a width of , we know that there will be two sides of length and two sides of width . Therefore:

### Example Question #4 : Polygons

What is the perimeter of a right triangle with a base of and a height of ?

**Possible Answers:**

Not enough information provided

**Correct answer:**

In order to find the perimeter of the right triangle, we need to know the lengths of each of its sides. While we are given two sides - the base and the height - we do not know the hypotenuse . There are two ways that we can find , the first of which is the direct application of the Pythagorean Theorem:

We could have also noted that is a common Pythagorean Triple and deduced the value of that way.

Now that we have all three side lengths, we can calculate :

### Example Question #5 : Polygons

What is the perimeter of an octagon with equal side lengths of each?

**Possible Answers:**

**Correct answer:**

Starting with the knowledge that we are dealing with an octagon, an 8-sided figure, we calculate the perimeter by adding the lengths of all 8 sides. Since we also know that each side measures , we can use multiplication:

### Example Question #6 : Polygons

is a pentagon with two sets of congruent sides and one side that is longer than all the others.

The smallest pair of congruent sides are 5 inches long each.

The other two congruent sides are 1.5 times bigger than the smallest sides.

The last side is twice the length of the smallest sides.

What is the perimeter of ?

**Possible Answers:**

**Correct answer:**

A pentagon is a 5 sided shape. We are given that two sides are 5 inches each.

Side 1 = 5inches

Side 2 = 5 inches

The next two sides are each 1.5 times bigger than the smallest two sides.

Side 3 =Side 4= 7.5 inches

The last side is twice the size of the smallest side,

Side 5 =10 inches

Add them all up for our perimeter:

5+5+7.5+7.5+10=35 inches long

### Example Question #7 : Polygons

One side of a regular dodecagon has a length of . What is the perimeter of the polygon?

**Possible Answers:**

**Correct answer:**

A regular dodecagon is a polygon with twelve sides of equal length, so if one side has a length of , then the perimeter will be equal to twelve times the length of that one side. This gives us:

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