### All College Algebra Resources

## Example Questions

### Example Question #1 : Finding Zeros Of A Polynomial

Find the roots of the function:

**Possible Answers:**

**Correct answer:**

Factor:

Double check by factoring:

Add together:

Therefore:

### Example Question #5 : Solving Quadratic Functions

Solve for x.

**Possible Answers:**

x = 5, 2

x = –4, –3

x = 4, 3

x = 5

x = –5, –2

**Correct answer:**

x = 5, 2

1) Split up the middle term so that factoring by grouping is possible.

Factors of 10 include:

1 * 10= 10 1 + 10 = 11

2 * 5 =10 2 + 5 = 7

–2 * –5 = 10 –2 + –5 = –7 Good!

2) Now factor by grouping, pulling "x" out of the first pair and "-5" out of the second.

3) Now pull out the common factor, the "(x-2)," from both terms.

4) Set both terms equal to zero to find the possible roots and solve using inverse operations.

x – 5 = 0, x = 5

x – 2 = 0, x = 2

### Example Question #3 : How To Simplify Binomials

Solve for :

**Possible Answers:**

**Correct answer:**

To solve for , you need to isolate it to one side of the equation. You can subtract the from the right to the left. Then you can add the 6 from the right to the left:

Next, you can factor out this quadratic equation to solve for . You need to determine which factors of 8 add up to negative 6:

Finally, you set each binomial equal to 0 and solve for :

### Example Question #7 : Solving Quadratic Functions

Find the roots of the following quadratic expression:

**Possible Answers:**

**Correct answer:**

First, we have to know that "finding the roots" means "finding the values of x which make the expression =0." So basically we are going to set the original expression = 0 and factor.

This quadratic looks messy to factor by sight, so we'll use factoring by composition. We multiply a and c together, and look for factors that add to b.

So we can use 8 and -3. We will re-write 5x using these numbers as 8x - 3x, and then factor by grouping.

Note the extra + sign we inserted to make sure the meaning is not lost when parentheses are added. Now we identify common factors to be "pulled" out.

Now we factor out the (3x + 4).

Setting each factor = 0 we can find the solutions.

So the solutions are x = 1/2 and x = -4/3, or {-4/3, 1/2}.

### Example Question #355 : Intermediate Single Variable Algebra

Find the roots of .

**Possible Answers:**

**Correct answer:**

If we recognize this as an expression with form , with and , we can solve this equation by factoring:

and

and

### Example Question #74 : Polynomial Functions

If the following is a zero of a polynomial, find another zero.

**Possible Answers:**

**Correct answer:**

When finding zeros of a polynomial, you must remember your rules. Without a function this may seem tricky, but remember that non-real solutions come in conjugate pairs. Conjugate pairs differ in the middle sign. Thus, our answer is:

### Example Question #75 : Polynomial Functions

**Possible Answers:**

**Correct answer:**

### Example Question #2 : Finding Zeros Of A Polynomial

**Possible Answers:**

**Correct answer:**

### Example Question #77 : Polynomial Functions

**Possible Answers:**

**Correct answer:**

### Example Question #78 : Polynomial Functions

**Possible Answers:**

**Correct answer:**