# Calculus 2 : Volume of a Solid

## Example Questions

← Previous 1

### Example Question #1 : Volume Of Cross Sections And Area Of Region

Determine the volume of the solid obtained by rotating the region with the following bounds about the x-axis:

Explanation:

From calculus, we know the volume of an irregular solid can be determined by evaluating the following integral:

Where A(x) is an equation for the cross-sectional area of the solid at any point x. We know our bounds for the integral are x=1 and x=4, as given in the problem, so now all we need is to find the expression A(x) for the area of our solid.

From the given bounds, we know our unrotated region is bounded by the x-axis (y=0) at the bottom, and by the line y=x^2-4x+5 at the top. Because we are rotating about the x-axis, we know that the radius of our solid at any point x is just the distance y=x^2-4x+5. Now that we have a function that describes the radius of the solid at any point x, we can plug the function into the formula for the area of a circle to give us an expression for the cross-sectional area of our solid at any point:

We now have our equation for the cross-sectional area of the solid, which we can integrate from x=1 to x=4 to find its volume:

### Example Question #2 : Volume Of Cross Sections And Area Of Region

Suppose the functions , and  form a closed region. Rotate this region across the x-axis. What is the volume?

Explanation:

Write the formula for cylindrical shells, where  is the shell radius and  is the shell height.

Determine the shell height.  This is done by subtracting the right curve, , with the left curve, .

Find the intersection of  and  to determine the y-bounds of the integral.

The bounds will be from 0 to 2.  Substitute all the givens into the formula and evaluate the integral.

### Example Question #3 : Volume Of Cross Sections And Area Of Region

Find the volume of the solid generated by revolving the region bounded by  and the -axis in the first quadrant about the -axis.

Explanation:

Since we are revolving a region of interest around a horizontal line , we need to express the inner and outer radii in terms of x.

Recall the formula:

The outer radius is  and the inner radius is . The x-limits of the region are between  and . So the volume set-up is:

Using trigonometric identities, we know that:

Hence:

### Example Question #71 : Integrals

A man fills up a cup of water by leaving it outside during a rainstorm. The rate at which the height of the cup changes is equal to . What is the height of water at ? Assume the cup is empty at .

Explanation:

The rate at which the height changes is , which means .

To find the height after nine seconds, we need to integrate to get .

We can multiply both sides by  to get  and then integrate both sides.

This gives us

.

Since the cup is empty at , so .

This means . No units were given in the problem, so leaving the answer unitless is acceptable.

### Example Question #72 : Integrals

Approximate the volume of a solid in the first quadrant revolved about the y-axis and bounded by the functions:   and .  Round the volume to the nearest integer.

Explanation:

Write the washer's method.

Set the equations equal to each other to determine the bounds.

The bounds are from 0 to 3.

Determine the big and small radius.  Rewrite the equations so that they are in terms of y.

Set up the integral and solve for the volume.

The volume to the nearest integer is:

### Example Question #73 : Integrals

Determine the volume of a solid created by rotating the curve  and the line  by revolving around the -axis.

Explanation:

Write the volume formula for cylindrical shells.

The shell height is the function in terms of .  Rewrite that equation.

The bounds lie on the y-axis since the thickness variable is .  This is from 0 to 1, since the intersection of the line  and  is at .

Substitute all the values and solve for the volume.

### Example Question #74 : Integrals

What is the volume of the solid formed when the line  is rotated around the -axis from  to ?

Explanation:

To rotate a curve around the y-axis, first convert the function so that y is the independent variable by solving  for x. This leads to the function

We'll also need to convert the endpoints of the interval to y-values. Note that when , and when  Therefore, the the interval being rotated is from .

The disk method is best in this case. The general formula for the disk method is

, where V is volume,  are the endpoints of the interval, and  the function being rotated.

Substuting the function and endpoints from the problem at hand leads to the integral

.

To evaluate this integral, you must know the power rule. Recall that the power rule is

.

### Example Question #75 : Integrals

Find the volume of the solid generated when the function

is revolved around the x-axis on the interval .

Hint: Use the method of cylindrical disks.

units cubed

units cubed

units cubed

units cubed

units cubed

Explanation:

The formula for the volume is given as

where  and the bounds on the integral come from the interval .

As such,

When taking the integral, we will use the inverse power rule which states

Applying this rule we get

And by the corollary of the First Fundamental Theorem of Calculus

As such,

units cubed

### Example Question #1 : Volume Of A Solid

Find the volume V of a solid whose cross section at x is a quarter circle with radius 2x on the interval [0, 3].

Explanation:

To determine the volume of a solid with defined cross sectional areas, the equation

where  is the cross sectional area at a given x, and the volume exists on the interval .

Because the cross sectional area is a quarter of a circle with a radius of 2x, we find

The volume is then found with

### Example Question #2 : Volume Of A Solid

Let R be the region between the graph of  and the x-axis on the interval .  Find the volume V of the solid obtained by revolving R about the x-axis.

Explanation:

The volume of solid region rotated around the x-axis such as the one in this problem can be found by summing the area of discs, using the formula :

where f(x) gives the radius of each disk.  Applying the equation for this problem:

← Previous 1