Calculus 2 : Definite Integrals

Study concepts, example questions & explanations for Calculus 2

varsity tutors app store varsity tutors android store

Example Questions

← Previous 1 3 4 5 6 7 8 9 25 26

Example Question #1 : Definite Integrals

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

The definite integral  can be integrated as is:

Evaluate the bounds.  Be aware of the sign changes.

 

 

Example Question #365 : Integrals

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

Be careful, we are integrating with the respect to y, not x.  This means that the integrand itself is treated as a constant.

Since we just have a constant, to integrate means to increase the value of the variable y. Thus we get the following,

.

From here we plug in our bounds. We take the upper bound function value and subtract lower bound function value.

Example Question #366 : Integrals

Calculate the following definite integral.

 

Possible Answers:

Correct answer:

Explanation:

To help us evalute the integral, we can split up the expression into 3 parts:

.

This allows us to evaluate the integral of each of the three parts, sum them up, and then evaluate the summed up parts from 0 to 1.

The first integral is .

The second integral is .

The third integral is .

Sum up all these terms in evaluate between 0 and 1.

Example Question #367 : Integrals

Evaluate the following integral:

Possible Answers:

Correct answer:

Explanation:

The general expression for the integral of a sine function is:

Using this, the integral above now becomes,

, which simplifies to

Example Question #2 : Definite Integrals

Evaluate the following integral:

Possible Answers:

Correct answer:

Explanation:

To integrate, we must first make the following subsitution:

The derivative was found using the following rules:

Now, rewrite the given integral, change the bounds in terms of  (by plugging in the upper and lower bounds into the equation for  in terms of ), and integrate:

The integral was performed using the following rule:

To perform the definite integration, simply plug in the upper limit of integration and subtract from the result of plugging in the lower limit of integration, as shown above. Simplifying the result, we get 

 

 

Example Question #3 : Definite Integrals

Calculate the value of the definite integral.

Possible Answers:

Correct answer:

Explanation:

In order to calculate the definite integral, we apply the inverse power rule which states

Applying this to the problem in this question term by term we get

And by the corollary of the Fundamental Theorem of Calculus the definite integral becomes

And so

Example Question #21 : Finding Integrals

Calculate the value of the definite integral.

Possible Answers:

Correct answer:

Explanation:

In order to calculate the definite integral, we apply the inverse power rule which states

Applying this to the problem in this question we get

And by the corollary of the Fundamental Theorem of Calculus the definite integral becomes

And so

Example Question #22 : Finding Integrals

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

The integral can be rewritten as:

The integration of a constant is simply the constant times the variable it is integrating with respect to.  Plug in the upper bound and subtract after substituting the lower bound.

There is no need to add a  term at the end when we are dealing with definite integrals.

The answer is:  

Example Question #23 : Finding Integrals

Evaluate:  

Possible Answers:

Correct answer:

Explanation:

Integrate each term.

Substitute the upper bound and subtract the quantity after substituting of the lower bound.

The right hand side of the equation becomes:

Convert all fraction to the least common denominator.

Simplify the terms.

The answer is:  

Example Question #24 : Finding Integrals

Solve the integral:

Possible Answers:

None of the chocies.

Correct answer:

Explanation:

Must choose what which term is  or .

, take the derivative to get  

, integrate to get 

Plug into parts into the equation:
  

Integrating again, while including the bounds gives:

  

 

← Previous 1 3 4 5 6 7 8 9 25 26
Learning Tools by Varsity Tutors

Incompatible Browser

Please upgrade or download one of the following browsers to use Instant Tutoring: