### All AP Physics 2 Resources

## Example Questions

### Example Question #3 : Electricity And Magnetism

Suppose that a proton moves perpendicularly through a magnetic field at a speed of . If this proton experiences a magnetic force of , what is the strength of the magnetic field?

.

**Possible Answers:**

**Correct answer:**

To solve this question, we need to relate the speed and charge of the particle with the magnetic force it experiences in order to solve for the magnetic field strength. Thus, we'll need to use the following equation:

Also, we are told that the particle is moving perpendicularly to the magnetic field.

Rearrange to solve for the magnetic field, then plug in known values and solve.

### Example Question #5 : Electricity And Magnetism

Suppose that a positively charged particle with charge moves in a circular path of radius in a constant magnetic field of strength . If the magnetic field strength is doubled to , what effect does this have on the radius of the circular path that this charge takes?

**Possible Answers:**

**Correct answer:**

To answer this question, we need to realize that the particle is moving in a circular path because of some sort of centripetal force. Since the charge is moving while within a constant magnetic field, we can conclude that it is the magnetic force that is responsible for the centripetal force that keeps this charge moving in a circle. Thus, we need to relate the centripetal force to the magnetic force.

The above equation shows us that the radius of the circular path is directy proportional to the mass and velocity of the particle, and inversely proportional to the charge of the particle and the magnetic field strength. Thus, if the value of the magnetic field is doubled, the above equation predicts that the value of the radius would be cut in half.

### Example Question #1 : Magnetic Fields

loops of current carrying wire form a solenoid of length that carries and have radius . Determine the magnetic field at the center of the solenoid.

**Possible Answers:**

**Correct answer:**

Using:

Where:

is the magnetic field

is the number of coils

is the current in the solenoid

is the length of the solenoid

is

Plugging in values:

### Example Question #5 : Electricity And Magnetism

There is a loop with a radius of and a current of . Determine the magnitude of the magnetic field at the center of the loop.

**Possible Answers:**

None of these

**Correct answer:**

Using the Biot-Savart law:

Where is the radius of the loop

is the current

is the distance from the center of the loop

Plugging in values:

### Example Question #6 : Electricity And Magnetism

A circular circuit is powered by a battery. How will the magnetic field change if the battery is removed and placed in the opposite direction?

**Possible Answers:**

The magnetic field will double in magnitude and flip directions

The magnetic field will become zero

None of these

The magnetic field will have the same magnitude and direction

The magnetic field will have the same magnitude, albeit in the opposite direction

**Correct answer:**

The magnetic field will have the same magnitude, albeit in the opposite direction

Reversing the battery will reverse the direction of the current. Using the right hand rule, it can be seen that this will also reverse the direction of the magnetic field. Since the magnitude of the current stays the same, the magnitude of the magnetic field will as well.

### Example Question #7 : Electricity And Magnetism

A circular circuit is powered by a battery. How will the magnetic field change if a second battery is added in the same direction as the first?

**Possible Answers:**

The magnetic field will become zero

The magnetic field will stay the same

The magnetic field will double in magnitude and have the same direction.

None of these

The magnetic field will quadruple

**Correct answer:**

The magnetic field will double in magnitude and have the same direction.

Based on the Biot-Savart law:

Doubling the voltage will double the current, which will double the magnetic field. The direction will stay the same.

### Example Question #8 : Electricity And Magnetism

If the north end of a magnetic points towards the geographic north pole, that means that the geographic north pole is a magnetic __________ pole.

**Possible Answers:**

None of these

Electrical

Mono

South

North

**Correct answer:**

South

Magnets will align themselves with the surrounding magnetic field. Thus, if the north pole of a magnet is pointing north, the direction of the magnetic field must be pointing north. Magnetic fields point towards magnetic south poles, so the geographic north pole is actually a magnetic south pole.

### Example Question #2 : Magnetic Fields

An infinitely long wire carries a current of determine the magnitude of the magnetic field away.

**Possible Answers:**

None of these

**Correct answer:**

Magnetic field of an infinitely long wire:

Where

Plugging in values:

### Example Question #3 : Magnetic Fields

A circuit contains a battery and a resistor in series. Determine the magnitude of the magnetic field outside of the loop away from the wire.

**Possible Answers:**

None of these

**Correct answer:**

Using

Converting to and plugging in values

Determining current:

### Example Question #4 : Magnetic Fields

How strong would a magnetic field need to be in order to make a particle with a mass of and a charge of move in a circular path with a speed of and a radius of ?

**Possible Answers:**

**Correct answer:**

For this question, we are being asked to determine the magnetic field necessary to make a particle of a given mass and charge to move in a circular path with a given speed and radius.

To begin with, we can realize that the particle will be moving in a circular path. Thus, there is going to be a centripetal force associated with this circular motion. Moreover, because we know the particle will be present in a magnetic field, we can infer that the magnetic force will be the source of the centripetal force. Thus, we can start by writing out the expression for each of these forces, and then setting them equal to one another.

Rearranging the above expression to isolate the term for magnetic field, we arrive at the following expression.

Now, we can plug in the values given to us in the question stem to solve for the magnetic field strength.

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