### All AP Computer Science A Resources

## Example Questions

### Example Question #1 : Evaluating Boolean Expressions

**Consider the following code:**

int[] a = {8,4,1,5,1,5,6,2,4};

int b = 1;

boolean[] vals = new boolean[a.length];

for(int i = 0; i < a.length; i++) {

vals[i] = (a[i] - 1 > 4);

}

for(int i = 0; i < vals.length; i++) {

String s = "Duns Scotus";

if(!vals[i]) {

s = "Mithrandir";

}

System.out.println(s);

}

What is the output for the code above?

**Possible Answers:**

None of the others

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Mithrandir

Mithrandir

Mithrandir

Mithrandir

Mithrandir

Duns Scotus

Mithrandir

Mithrandir

Duns Scotus

Mithrandir

Mithrandir

Duns Scotus

Mithrandir

Duns Scotus

Mithrandir

Duns Scotus

Mithrandir

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Duns Scotus

Mithrandir

Duns Scotus

Duns Scotus

**Correct answer:**

Duns Scotus

Mithrandir

Mithrandir

Mithrandir

Mithrandir

Mithrandir

Duns Scotus

Mithrandir

Mithrandir

Begin by getting a general idea of the loop logic being executed. For each execution of the first loop, you are assigning a boolean to the *vals* array. Now, you could rewrite the code a little to make the math easier:

a[i] - 1 > 4

really is the same as:

a[i] > 5

Now, the only values for which this is true are:

8 and 6 (the first and the 7th values in *a*).

Now, looking at the second loop, the value *s* will be "Duns Scotus" for every value that is * true* in

*vals*. This is because the if statement checks for

**!vals[i]**. Thus, the first and the seventh values alone will be "Duns Scotus". Everything else will be "Mithrandir".

### Example Question #51 : Standard Data Structures

**Consider the following code:**

int a = 14;

int b = -15;

int c = 22;

int d = 11;

if(a > 12 && b < -14 && c < d) {

System.out.println("YAY!!!!");

} else if (d - 20 < b) {

System.out.println("GO DO MORE PROGRAMMING!");

} else if(a + 12 >= c) {

System.out.println("This is vexing......");

} else {

System.out.println("This is very fun!");

}}

What is the output for the code above?

**Possible Answers:**

This is vexing......

GO DO MORE PROGRAMMING!

This is very fun!

YAY!!!!

No output appears.

**Correct answer:**

This is vexing......

Consider each condition:

The first if statement has: a > 12 && b < -14 && c < d

While it is true that 14 > 12 and -15 < -14, it is not true that 11 < 22. Therefore, the conjunction of all of these cannot be true. For &&, all of the expressions must be true.

Next, consider: d - 20 < b

This is really: 11 - 20 < -15 or -9 < -15. This is not true either.

Next, consider: a + 12 >= c

This is really: 12 + 12 >= 22 or 24 >= 22. This is true. Therefore, your output is "This is vexing......"!

### Example Question #2 : Evaluating Boolean Expressions

**Consider the code below: **

`for(int i = 0; i < 10; i++) {`

` if(i % 2 == 0) {`

` System.out.println("This is my favorite case!");`

` } else if(i + 6 > 12 && i % 3 == 1) {`

` System.out.println("There once was a pool in the back yard!");`

` } else {`

` System.out.println("Well, at least it is something...");`

` }`

`}`

What is the output for the code above?

**Possible Answers:**

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`This is my favorite case!`

`There once was a pool in the back yard!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`There once was a pool in the back yard!`

`Well, at least it is something...`

`This is my favorite case!`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`This is my favorite case!`

`There once was a pool in the back yard!`

`This is my favorite case!`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`There once was a pool in the back yard!`

`This is my favorite case!`

`Well, at least it is something...`

**Correct answer:**

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`Well, at least it is something...`

`This is my favorite case!`

`There once was a pool in the back yard!`

`This is my favorite case!`

`Well, at least it is something...`

First of all, note that your loop will run for values from 0 to 9, inclusive.

Now, the first condition is relatively easy:

`i % 2 == 0`

This is true when the number `i`

is even. When it is divisible by 2, the remainder will be 0. (Recall that the modulus gives you the remainder.)

Now, the next two `else`

conditions will execute only for odd numbers. The first one can be rewritten:

`i > 6 && i % 3 == 1`

This means that we need all of the numbers from 7 to 9 that have a remainder of 1 when divided by 3. This only applies to `i = 7`

. This will be the eighth line output. Therefore, you know that you will have alternating lines saying, "This is my favorite case!" All of the other ones will be "Well, at least it is something...", except for the eighth line, which will be "There once was a pool in the back yard!"

### Example Question #53 : Standard Data Structures

**Consider the code below:**

`int i = 45, j = -12;`

`String s = "This is great!";`

`String s2 = "Where are you?";`

`if(s2.charAt(4) == ' ' && (i < 4 || j > -43) && !s2.equals("WOW!!!")) {`

` System.out.println("Happy days are here again!");`

`} else if (s2.charAt(5) == 's') {`

` System.out.println("Well, we are here at least.");`

`} else if (j + 12 != 0) {`

` System.out.println("The stock market is up today!");`

`} else if(i - 20 < 100) {`

` System.out.println("Where will we be having lunch tomorrow?");`

`} else {`

` System.out.println("But here you go!");`

`}`

What is the output for the code above?

**Possible Answers:**

`Well, we are here at least.`

`Where will the group be having lunch tomorrow?`

`The stock market is up today!`

`But here you go!`

`Happy days are here again!`

**Correct answer:**

`Where will the group be having lunch tomorrow?`

The easiest way to begin is by looking at the general form of the first `if`

statement. Notice that it is made up of three expressions that have a boolean `AND`

between them. This means that if any of those members is false, the whole thing will be false. Well, consider the very first term:

`s2.charAt(4) == ' '`

This is asking about the fifth character in the string `s2`

. (Remember, the index starts at 0.) Well, this is true for `s`

but not for `s2`

, which has '`e`

' for its fifth member. Thus, we know that the first `if`

must be false.

Now, to the second:

`s2.charAt(5) == 's'`

This also is not true, for the sixth character in `s2`

is `' '`

.

The third `if`

is also false. `j + 12`

is equal to 0!

However, it is indeed the case that `(45 - 20 < 100)`

is true. Therefore, the fourth `if`

statement will execute, giving you the output:

`Where will the group be having lunch tomorrow?`

### Example Question #54 : Standard Data Structures

**Consider the code below: **

`int i = 12, j = -5, k = 103;`

`if(i < 15 && j >= -4) {`

` System.out.println("You should take more philosophy classes!");`

`} else if(!(i < 100 && k > 4)) {`

` System.out.println("I love medieval studies!");`

`} else if(!(i == 3 && k == 4)) {`

` System.out.println("My favorite philosopher is Radulphus Brito, of course!");`

`} else if(i != 4 && k == 102) {`

` System.out.println("My favorite philosopher is Johann Fichte.");`

`} else {`

` System.out.println("I am going to cut the grass tomorrow.");`

`}`

What is the output for the code above?

**Possible Answers:**

`I love medieval studies!`

`My favorite philosopher is Johann Fichte.`

`I am going to cut the grass tomorrow.`

`You should take more philosophy classes!`

`My favorite philosopher is Radulphus Brito, of course!`

**Correct answer:**

`My favorite philosopher is Radulphus Brito, of course!`

Let us consider each conditional in turn. When we reach one that is true, we know our output.

**First Conditional:** `i < 15 && j >= -4`

Recall that you must have both of these true in order for the whole expression to be true. Well, while it is the case that , it is not true that . Thus, this conditional is false.

**Second Conditional: ** `!(i < 100 && k > 4)`

For this, you must first attempt the expression in parentheses. Both of these are true. However, `!(true)`

is false. (It makes sense in English: "That is not true!" This means, "That is false!")

**Third Conditional: ** `!(i == 3 && k == 4)`

Well, here, we know that both `12 == 3`

and `103 == 4`

are both false. Therefore, the expression is `!(false)`

. Therefore, it is true! This is your output.

### Example Question #55 : Standard Data Structures

**Consider the code below: **

`char c = 'M';`

`String s = "James of Metz";`

`String s2 = "Albert of Sazony";`

`int i = 14;`

`if(i > 34 || c < 'B') {`

` System.out.println("I love Duns Scotus!");`

`} else if(s.charAt(9) == c) {`

` System.out.println("I read William of Ockham yesterday!");`

`} else if(!(i < 100 || s.equals("James of Metz"))) {`

` System.out.println("Well, I call William of Ockham 'Bill' because we're BFFs.");`

`} else if(s2.equalsIgnoreCase("Al")) {`

` System.out.println("I was reading Simon of Faversham, and he is very logical.");`

`} else {`

` System.out.println("There is nobody like Peter of Spain for a good logic read.");`

`}`

What is the output for the code above?

**Possible Answers:**

I read William of Ockham yesterday!

I was reading Simon of Faversham, and he is very logical.

There is nobody like Peter of Spain for a good logic read.

Well, I call William of Ockham 'Bill' because we're BFFs.

I love Duns Scotus!

**Correct answer:**

I read William of Ockham yesterday!

Let's consider the cases in order until we find our matching true expression.

**Conditional 1: **`i > 34 || c < 'B'`

All we need is for one of these to be true for the whole expression to be true (given the nature of the logical OR represented by `||`

. However, neither of these are true.

**Conditional 2: **`s.charAt(9) == c`

If you carefully count the letters in the String `s`

, you will see that index 9 (i.e. the tenth character) is `M`

. Therefore, this is equal to `c`

. Thus, you know that your program will output `I read William of Ockham yesterday!`

### Example Question #3 : Evaluating Boolean Expressions

What does the expression (7 != 14) evaluate to?

**Possible Answers:**

7

False

2

True

14

**Correct answer:**

True

The "!" symbol means not. Therefore, 7 does not equal 14 is true.

### Example Question #4 : Evaluating Boolean Expressions

boolean x;

int y;

x = false;

y = 10;

x = !(y < 10 || y > 10);

System.out.println ( x );

What is printed?

**Possible Answers:**

x

5

True

False

10

**Correct answer:**

True

The expression !(y < 10 || y > 10) evaluates to (y >= 10 && y <= 10).

Since y = 10, the expression evaluates to true.

### Example Question #58 : Standard Data Structures

What does this statement return?

int a = 2

int b = 3

a == b

**Possible Answers:**

null

indeterminate

true

false

**Correct answer:**

false

a and b are both primitive types of integer. a is equal to 2 and b is equal to 3. 2 does not equal 3, so the answer is false.

### Example Question #5 : Evaluating Boolean Expressions

Which is correct?

String a = "2"

String b = "2"

Is a == b correct? Or is a.equals(b) correct?

**Possible Answers:**

Neither is correct

Both answers have the same result

a == b

a.equals(b)

**Correct answer:**

a.equals(b)

Since both objects are not primitive types, double equals, ==, would return whether the pointers of the type objects are equivalent. The string object requires the string equals method which is String.eq("string")

### All AP Computer Science A Resources

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