### All AP Calculus BC Resources

## Example Questions

### Example Question #82 : Polynomial Approximations And Series

Determine if the following series is divergent, convergent or neither.

**Possible Answers:**

Neither

Inconclusive

Both

Convergent

Divergent

**Correct answer:**

Convergent

In order to figure out if

is divergent, convergent or neither, we need to use the ratio test.

Remember that the ratio test is as follows.

Suppose we have a series . We define,

Then if

, the series is absolutely convergent.

, the series is divergent.

, the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply the ratio test to our problem.

Let

and

Now

Now lets simplify this expression to

.

Since

.

We have sufficient evidence to conclude that the series is convergent.

### Example Question #83 : Polynomial Approximations And Series

Determine if the following series is divergent, convergent or neither.

**Possible Answers:**

Divergent

Neither

Convergent

Inconclusive

Both

**Correct answer:**

Divergent

In order to figure if

is convergent, divergent or neither, we need to use the ratio test.

Remember that the ratio test is as follows.

Suppose we have a series . We define,

Then if

, the series is absolutely convergent.

, the series is divergent.

, the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply the ratio test to our problem.

Let

and

Now

.

Now lets simplify this expression to

.

Since ,

we have sufficient evidence to conclude that the series is divergent.

### Example Question #1 : Ratio Test And Comparing Series

Determine if the following series is divergent, convergent or neither.

**Possible Answers:**

Both

Convergent

Divergent

Neither

Inconclusive

**Correct answer:**

Divergent

In order to figure if

is convergent, divergent or neither, we need to use the ratio test.

Remember that the ratio test is as follows.

Suppose we have a series . We define,

Then if

, the series is absolutely convergent.

, the series is divergent.

, the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply the ratio test to our problem.

Let

and

.

Now

.

Now lets simplify this expression to

.

Since ,

we have sufficient evidence to conclude that the series is divergent.

### Example Question #2 : Ratio Test And Comparing Series

Determine if the following series is convergent, divergent or neither.

**Possible Answers:**

Convergent

More tests are needed.

Neither

Divergent

Inconclusive

**Correct answer:**

Divergent

To determine if

is convergent, divergent or neither, we need to use the ratio test.

The ratio test is as follows.

Suppose we a series . Then we define,

.

If

the series is absolutely convergent (and therefore convergent).

the series is divergent.

the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply this to our situtation.

Let

and

Now

We can rearrange the expression to be

Now lets simplify this.

When we evaluate the limit, we get.

.

Since , we have sufficient evidence to conclude that the series diverges.

### Example Question #3 : Ratio Test And Comparing Series

Determine if the following series is divergent, convergent or neither.

**Possible Answers:**

Divergent

More tests are needed.

Neither

Convegent

Inconclusive

**Correct answer:**

Convegent

To determine if

is convergent, divergent or neither, we need to use the ratio test.

The ratio test is as follows.

Suppose we a series . Then we define,

.

If

the series is absolutely convergent (and thus convergent).

the series is divergent.

the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply this to our situtation.

Let

and

Now

We can rearrange the expression to be

.

Now lets simplify this.

When we evaluate the limit, we get.

.

Since , we have sufficient evidence to conclude that the series converges.

### Example Question #87 : Polynomial Approximations And Series

Determine if the following series is convergent, divergent or neither.

**Possible Answers:**

Convergent

More tests needed.

Divergent

Neither

Inconclusive

**Correct answer:**

Divergent

To determine if

is convergent, divergent or neither, we need to use the ratio test.

The ratio test is as follows.

Suppose we a series . Then we define,

.

If

the series is absolutely convergent (therefore convergent).

the series is divergent.

the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply this to our situtation.

Let

and

Now

We can rearrange the expression to be

Now lets simplify this.

When we evaluate the limit, we get.

.

Since , we have sufficient evidence to conclude that the series diverges.

### Example Question #4 : Ratio Test And Comparing Series

Determine if the following series is divergent, convergent or neither.

**Possible Answers:**

Convergent

Neither

Inconclusive

More tests are needed.

Divergent

**Correct answer:**

Divergent

To determine if

is convergent, divergent or neither, we need to use the ratio test.

The ratio test is as follows.

Suppose we a series . Then we define,

.

If

the series is absolutely convergent (and thus convergent).

the series is divergent.

the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply this to our situtation.

Let

and

Now

We can simplify the expression to be

When we evaluate the limit, we get.

.

Since , we have sufficient evidence to conclude that the series diverges.

### Example Question #5 : Ratio Test And Comparing Series

Determine of the following series is convergent, divergent or neither.

**Possible Answers:**

Divergent

Inconclusive.

Neither

More tests are needed.

Convergent

**Correct answer:**

Divergent

To determine whether this series is convergent, divergent or neither

we need to remember the ratio test.

The ratio test is as follows.

Suppose we a series . Then we define,

.

If

the series is absolutely convergent (and therefore convergent).

the series is divergent.

the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply this to our situtation.

Let

and

Now

We can rearrange the expression to be

Now lets simplify this to.

When we evaluate the limit, we get.

.

Since , we have sufficient evidence to conclude that the series is divergent.

### Example Question #90 : Polynomial Approximations And Series

Determine what the following series converges to using the ratio test and whether the series is convergent, divergent or neither.

**Possible Answers:**

, and neither.

, and convergent.

, and neither.

, and divergent.

, and convergent.

**Correct answer:**

, and convergent.

To determine whether this series is convergent, divergent or neither

we need to remember the ratio test.

The ratio test is as follows.

Suppose we a series . Then we define,

.

If

the series is absolutely convergent (thus convergent).

the series is divergent.

the series may be divergent, conditionally convergent, or absolutely convergent.

Now lets apply this to our situtation.

Let

and

Now

We can rearrange the expression to be

Now lets simplify this to.

When we evaluate the limit, we get.

.

Since , we have sufficient evidence to conclude that the series is convergent.

### Example Question #6 : Ratio Test And Comparing Series

Determine the convergence or divergence of the following series:

**Possible Answers:**

The series (absolutely) convergent.

The series may be divergent, conditionally convergent, or absolutely convergent.

The series is conditionally convergent.

The series is divergent.

**Correct answer:**

The series (absolutely) convergent.

To determine the convergence or divergence of this series, we use the Ratio Test:

If , then the series is absolutely convergent (convergent)

If , then the series is divergent

If , the series may be divergent, conditionally convergent, or absolutely convergent

So, we evaluate the limit according to the formula above:

which simplified becomes

Further simplification results in

Therefore, the series is absolutely convergent.

### All AP Calculus BC Resources

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