### All AP Calculus BC Resources

## Example Questions

### Example Question #18 : Introduction To Series In Calculus

One of the following infinite series CONVERGES. Which is it?

**Possible Answers:**

None of the others converge.

**Correct answer:**

converges due to the comparison test.

We start with the equation . Since for all values of k, we can multiply both side of the equation by the inequality and get for all values of k. Since is a convergent p-series with , hence also converges by the comparison test.

### Example Question #1 : P Series

Determine the nature of convergence of the series having the general term:

**Possible Answers:**

The series is divergent.

The series is convergent.

**Correct answer:**

The series is convergent.

We will use the Limit Comparison Test to establish this result.

We need to note that the following limit

goes to 1 as n goes to infinity.

Therefore the series have the same nature. They either converge or diverge at the same time.

We will focus on the series:

.

We know that this series is convergent because it is a p-series. (Remember that

converges if p>1 and we have p=3/2 which is greater that one in this case)

By the Limit Comparison Test, we deduce that the series is convergent, and that is what we needed to show.

### Example Question #2 : P Series

Determine if the series converges or diverges. You do not need to find the sum.

**Possible Answers:**

Conditionally converges.

Neither converges nor diverges.

There is not enough information to decide convergence.

Converges

Diverges

**Correct answer:**

Converges

We can compare this to the series which we know converges by the p-series test.

To figure this out, let's first compare to . For any number n, will be larger than .

There is a rule in math that if you take the reciprocal of each term in an inequality, you are allowed to flip the signs.

Thus, turns into

.

And so, because converges, thus our series also converges.

### Example Question #36 : Types Of Series

Which of the following tests will help determine whether is convergent or divergent, and why?

**Possible Answers:**

P-Series Test: The summation converges since .

Divergence Test: Since limit of the series approaches zero, the series must converge.

Nth Term Test: The series diverge because the limit as goes to infinity is zero.

Root Test: Since the limit as approaches to infinity is zero, the series is convergent.

Integral Test: The improper integral determines that the harmonic series diverge.

**Correct answer:**

Integral Test: The improper integral determines that the harmonic series diverge.

The series is a harmonic series.

The Nth term test and the Divergent test may not be used to determine whether this series converges, since this is a special case. The root test also does not apply in this scenario.

According the the P-series Test, must converge only if . Therefore this could be a valid test, but a wrong definition as the answer choice since the series diverge for .

This leaves us with the Integral Test.

Since the improper integral diverges, so does the series.

### Example Question #2 : P Series

Does the series converge conditionally, absolutely, or diverge?

**Possible Answers:**

Does not exist.

Cannot tell with the given information.

Diverges.

Converge Conditionally.

Converge Absolutely.

**Correct answer:**

Converge Conditionally.

The series converges conditionally.

The absolute values of the series is a divergent p-series with .

However, the the limit of the sequence and it is a decreasing sequence.

Therefore, by the alternating series test, the series converges conditionally.

### Example Question #3 : P Series

True or False, a -series cannot be tested conclusively using the ratio test.

**Possible Answers:**

True

False

**Correct answer:**

True

We cannot test for convergence of a -series using the ratio test. Observe,

For the series ,

.

Since this limit is regardless of the value for , the ratio test is inconclusive.

### All AP Calculus BC Resources

### Incompatible Browser

Please upgrade or download one of the following browsers to use Instant Tutoring: